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8_murik_8 [283]

3 years ago

5

A 270,000 kg rocket in gravity -free space expels 270 kg of fuel by exerting a force of 360 N on it. Find the magnitude of the a

cceleration of the fuel

1 answer:

Brut [27]3 years ago

4 0

F = m a
360 = 270 x a
1.3 = a

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1000 kg has 50, 000 joules of kinetic energy. what is it's speed?

kicyunya [14]

The answer is 36 kilometers per hour, or 10 meters per second.

7 0

3 years ago

A red cross helicopter takes off from headquarters and flies 120 km at 70 degrees south of west. There it drops off some relief

fiasKO [112]

Answer:

130 km at 35.38 degrees north of east

Explanation:

Suppose the HQ is at the origin (x = 0, y = 0)

So the coordinates of the helicopter after the 1st flight is

$x_1 = -120cos70^o = -41.04 km$

$y_1 = -120sin70^o = -112.763 km$

After the 2nd flight its coordinate would be:

$x_2 = x_1 - 75sin60^o = -41.04 - 64.95 = -106km$

$y_2 = y_1 + 75cos60^o = -112.763 + 37.5 = -75.263 km$

So in order to fly back to its HQ it must fly a distance and direction of

$s = \sqrt{y_2^2 + x_2^2} = \sqrt{75.263^2 + 106^2} = \sqrt{5664.519169 + 11236} = \sqrt{16900.519169} = 130 km$

$tan\theta = \frac{y_2}{x_2} = \frac{75.263}{106} = 0.71$

$\theta = tan^{-1}0.71 = 0.62 rad \approx 35.38^o$ north of east

3 0

3 years ago

An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis.

zhenek [66]

Answer:

2 m/s and -2 m/s

Explanation:

The object travels with an angle of

60.0°

with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).

If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:

$v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s$

If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:

$v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s$

5 0

3 years ago

You need to produce a set of cylindrical copper wire 3.5 m long that will have a

vazorg [7]

Solution :

We know, resistance is given by :

$R = \dfrac{\rho l}{A}$

$A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2$

Now, we know mass of wire is given by :

$Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram$

Hence, this is the required solution.

8 0

3 years ago

A flea jumps straight up to a maximum height of 0.400 m . what is its initial velocity v0 as it leaves the ground?

timama [110]

For an object`s motion, the Kinematic equation is,

$v^2=v_{0}^2+2ah$

Here, v is the final velocity and h is stands for the height of the object and a is the acceleration of the object.

As according to question,

$v=0m/s,a=g-9.8 m/s^2$ and $h = 0.400 m$

Thus, putting these values in above equation, we get

$0= v_{0}^2 -2gh$

or

$v_{0} =\sqrt{2 \times 9.8 \times 0.400 }$

$v_{0} = 2.8 m/s$

Therefore, initial velocity is 2.8 m/s

8 0

3 years ago