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OlgaM077 [116]
3 years ago
5

To what is amplitude related? (1 pointthe amount of energy carried by the wave the maximum displacement from the rest position n

either of the above both the first and the second choices above amplitude is related to both the amount of energy carried by the wave and the maximum displacement from the rest position . [ ] [ [ ] ]
Physics
1 answer:
Tamiku [17]3 years ago
4 0
Both the first and the second choices above 
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Particle q₁ has a charge of 2.7 μC and a velocity of 773 m/s. If it experiences a magnetic force of 5.75 × 10⁻³ N, what is the s
Ne4ueva [31]
The intensity of the magnetic force F experienced by a charge q moving with speed v in a magnetic field of intensity B is equal to
F=qvB \sin \theta
where \theta is the angle between the directions of v and B.

1) Re-arranging the previous formula, we can calculate the value of the magnetic field intensity. The charge is q=2.7 \mu C=2.7 \cdot 10^{-6}C. In this case, v and B are perpendicular, so \theta=90^{\circ}, therefore we have:
B= \frac{F}{qv \sin \theta} = \frac{5.75 \cdot 10^{-3}N}{(2.7 \cdot 10^{-6}C)(773m/s)\sin 90^{\circ}}=2.8 T

2) In this second case, the angle between v and B is \theta=55^{\circ}. The charge is now q=42.0 \mu C=42.0 \cdot 10^{-6}C, and the magnetic field is the one we found in the previous part, B=2.8 T, so we can find the intensity of the force experienced by this second charge:
F=qvB \sin \theta=(42\cdot 10^{-6}C)(1.21 \cdot 10^3 m/s)(2.8 T)(\sin 55^{\circ})=0.12 N
5 0
3 years ago
Read 2 more answers
A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the
Nitella [24]

Answer:

The magnitude of the force required to bring the mass to rest is 15 N.

Explanation:

Given;

mass, m = 3 .00 kg

initial speed of the mass, u = 25 m/s

distance traveled by the mass, d = 62.5 m

The acceleration of the mass is given as;

v² = u² + 2ad

at the maximum distance of 62.5 m, the final velocity of the mass = 0

0 = u² + 2ad

-2ad = u²

-a = u²/2d

-a = (25)² / (2 x 62.5)

-a = 5

a = -5 m/s²

the magnitude of the acceleration = 5 m/s²

Apply Newton's second law of motion;

F = ma

F = 3 x 5

F = 15 N

Therefore, the magnitude of the force required to bring the mass to rest is 15 N.

4 0
3 years ago
Name a situation when potential energy is useful
adell [148]
Gravitational energy is a form of potential energy because it is dependent on the mass of an object and needs to be calculated for the specific object.
3 0
3 years ago
4. (a) A tank containing methanol has walls 2.50 cm thick made of glass of refractive index 1.550. Light from the outside air st
zhenek [66]

Answer:

29.775°

1.911

Explanation:

Law of refraction(Snell's law):  

n_1 sin Ф_1 = n_2 sin Ф_2  

n_1 = The index of refraction for material with incident light,

n_2 = The index of refraction for material with refracted light

Ф_1= angle of incidence,

Ф_2 = angle of refraction.  

Note: the angle is measured from the normal: a line drawn perpendicular to the surface at the point where the incident ray strikes the surface.

The Part of the light which continues into the second medium is transmitted rather than reflected, but the transmitted ray changes direction as it crosses the boundary. The transmission of light from one medium to another, but with a change in direction, is called refraction. The angles of the incidence and reflected light is described by (Snells law) which is shown above.  

a)

n_3 = 1.329 —> for metalmol —> from table

1 —> in air

2 —> in the glass

3 —> in methanol  

from air to glass

n_1 sin Ф_1 = n_2 sin Ф_2  

1 x sin 41.3° =  1.550  sin Ф_2  

Ф_2 = arcsin(1*sin41.3°/1.550) = 25.201°

from glass to methanol:

n_2 sin Ф_2 = n_3 sin Ф_3  

1.550 sin 25.201° = 1.329 * sin Ф_3

Ф_3 = arcsin(1.550 sin 25.201°/1.329) = 29.775

from glass to unknown:

n_2 sin Ф_2 = n_3 sin Ф_3  

1.550 sin 25.201° = n_unknown * sin 20.2

n_unknown = 1.550 sin 25.201°/sin 20.2

                     = 1.911

5 0
3 years ago
The word that identifies the color of an object seen under ordinary daylight is:
IRINA_888 [86]
The word that identifies the colour of an object seen under ordinary daylight is local colour.
The natural colour of the object, it is best seen on a matte surface because it is not being reflected and therefore distorted. It is the presentation of features of a particular locality.
3 0
3 years ago
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