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OlgaM077 [116]
3 years ago
5

To what is amplitude related? (1 pointthe amount of energy carried by the wave the maximum displacement from the rest position n

either of the above both the first and the second choices above amplitude is related to both the amount of energy carried by the wave and the maximum displacement from the rest position . [ ] [ [ ] ]
Physics
1 answer:
Tamiku [17]3 years ago
4 0
Both the first and the second choices above 
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NEED HELP
aniked [119]

Answer:

I = 0.25 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.

V = I*R

where:

V = voltage [Volt]

I = amperage or current [amp]

R = resistance [ohm]

Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.

Rt = 2 + 8 + 14

Rt = 24 [ohm]

Now clearing I for amperage

I = V/Rt

I = 6/24

I = 0.25 [amp].

5 0
3 years ago
using hooke's law, f spring = k triangle x, find the elastic constant of a spring that stretches 2 cm when a 4 newton force is a
Ksivusya [100]

As we know that spring force is given as

F = kx

here we know that

F = 4 N

x = 2 cm = 0.02 m

now from the above equation we will have

4 = k(0.02)

k = 200 N/m

so the elastic constant of the spring will be 200 N/m

8 0
3 years ago
Which of the following organisms are known as producers?
timofeeve [1]

Answer:

A,B.D

Explanation:

4 0
3 years ago
Read 2 more answers
What aspect of speech sound is the primary factor in determining if one perceives the /ba/ sound or the /pa/ sound?
nignag [31]
The answer is voice onset time. It is a part of the production of stop consonants. Its definition is the length of time that passes between the release of a stop consonant and the start of the voicing and the vibration of the vocal folds.
3 0
2 years ago
Jorge wishes to observe the progress of his vacuum pump in evacuating a tall bell jar for the purpose of demonstrating that soun
natka813 [3]

Answer:

1.147 %

Explanation:

\rho = Density of mercury = 1.36\times 10^4\ kg/m^3

g = Acceleration due to gravity = 9.81 m/s²

h = Height of mercury = 8.69 m

Standard atmospheric pressure = 1.01\times 10^5\ Pa

6.55 mmHg converting to Pa

\rho gh\\ =1.36\times 10^4\times 9.81\times 8.69\times 10^{-3}\\ =1159.38504\ Pa

Dividing air pressure by the above value

\frac{1159.38504}{1.01\times 10^5}\times 100=1.147\ \%

The fraction of atmospheric pressure is 1.147 %

8 0
3 years ago
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