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OlgaM077 [116]
3 years ago
5

To what is amplitude related? (1 pointthe amount of energy carried by the wave the maximum displacement from the rest position n

either of the above both the first and the second choices above amplitude is related to both the amount of energy carried by the wave and the maximum displacement from the rest position . [ ] [ [ ] ]
Physics
1 answer:
Tamiku [17]3 years ago
4 0
Both the first and the second choices above 
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Emilio pushes a 100 kg freshman with 200 N of force. How much is the freshman accelerated?
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Explanation:

F = MA

200 = 100 * A

A = 200/100

A = 2m/sec^2

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Is 2/2 1 or 0? please help lol
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Answer:

1.

Explanation:

Hello!

In this case, for such mathematical operations, we can wee that the slash represents a fraction or a division, say 8 ÷ 4 = 2, 6 ÷ 3 = 2, 20 ÷ 4 = 5, etc. In such a way, since the operation 2/2, represents 2 ÷ 2, it is clear that two is once in 2, therefore, the result is:

2 ÷ 2 = 1.

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How would the number 13,900 be written using scientific notation?
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2 years ago
A man strikes one end of a thin rod with a hammer. The speed of sound in the rod is 15 times the speed of sound in air. A woman,
lina2011 [118]

Answer:

44.1 m

Explanation:

<u>Given:</u>

  • V_a = speed of sound in air = 343 m/s
  • V_r = speed of sound in the rod = 15V_a
  • \Delta t = times interval between the hearing the sound twice = 0.12 s

<u>Assumptions:</u>

  • l = length of the rod
  • t = time taken by the sound to travel through the rod
  • T = time taken by the sound to travel to through air to the same point = t+\Delta t = t+0.12\ s

We know that the distance traveled by the sound in a particular medium is equal to the product of the speed of sound in that medium and the time taken.

For traveling sound through the rod, we have

l=V_r t\\\Rightarrow t = \dfrac{l}{V_r}..........eqn(1)

For traveling sound through the air to the women ear for traveling the same distance, we have

l=V_aT\\\Rightarrow l=V_a(t+0.12)\\\Rightarrow l=V_a(\dfrac{l}{V_r}+0.12)\,\,\,\,\,\,(\textrm{From eqn (1)})\\\Rightarrow l=V_a(\dfrac{l}{15V_a}+0.12)\\\Rightarrow l=\dfrac{l}{15}+0.12V_a\\\Rightarrow l-\dfrac{l}{15}=0.12V_a\\\Rightarrow \dfrac{14l}{15}=0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = 44.1\ m

Hence, the length of the rod is 44.1 m.

4 0
3 years ago
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