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3 years ago

12

If a particular atom of an element has five protons a neutral atom of this element would have ________ electrons. A. 0 B. 3 C. 5

D. 8

2 answers:

Bezzdna [24]3 years ago

5 0

C. 5

a neutral atom has no electrical charge. protons are positive and electrons are negative, they need to be the same to make it a neutral atom.

Ierofanga [76]3 years ago

5 0

Proton = Electron. So the answer is 5

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The cause of a fire in a computer is described as an incorrectly wired circuit.

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2. A Zambia police car traveling at 25 m/s slows down at a rate of at 3.5 m/s

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3 years ago

A 481-m long spaceship passes by an observer at the speed of 2.70×10^8 m/s. What length does the observer measure for the spaces

galben [10]

Answer:

209.66 m

Explanation:

Given:

Original length of the spaceship, L = 481 m

Speed of the spaceship, v = 2.70 × 10⁸ m/s

Now,

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$L=\frac{L'}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

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c is the speed of the light

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on substituting the respective values, we get

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or

L' = 209.66 m

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4 years ago

A lamp with a resistance of 60 Ohms is plugged into a 110-Volt household circuit. How much current flows through the lamp?

Mrac [35]

The current flowing through the lamp is 1.833A

<h3>What is current?</h3>

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

From the Ohm's law, V =IR

Here, R is the proportionality constant called resistance of the resistor

A lamp with a resistance of 60 Ohms is plugged into a 110-Volt household circuit.

I = V/R

Put the values, we get

I = 110/60

I = 1.833A

Thus, the current flowing through the lamp is 1.833A

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2 years ago

A sound source A and a reflecting surface B move directly toward each other. Relative to the air, the speed of source A is 28.7

aleksandrvk [35]

(a) 1440.5 Hz

The general formula for the Doppler effect is

$f'=(\frac{v+v_r}{v+v_s})f$

where

f is the original frequency

f is the apparent frequency

$v$ is the velocity of the wave

$v_r$ is the velocity of the receiver (positive if the receiver is moving towards the source, negative otherwise)

$v_s$ is the velocity of the source (positive if the source is moving away from the receiver, negative otherwise)

Here we have

f = 1110 Hz

v = 334 m/s

In the reflector frame (= on surface B), we have also

$v_s = v_A = -28.7 m/s$ (surface A is the source, which is moving towards the receiver)

$v_r = +62.2 m/s$ (surface B is the receiver, which is moving towards the source)

So, the frequency observed in the reflector frame is

$f'=(\frac{334 m/s+62.2 m/s}{334 m/s-28.7 m/s})1110 Hz=1440.5 Hz$

(b) 0.232 m

The wavelength of a wave is given by

$\lambda=\frac{v}{f}$

where

v is the speed of the wave

f is the frequency

In the reflector frame,

f = 1440.5 Hz

So the wavelength is

$\lambda=\frac{334 m/s}{1440.5 Hz}=0.232 m$

(c) 1481.2 Hz

Again, we can use the same formula

$f'=(\frac{v+v_r}{v+v_s})f$

In the source frame (= on surface A), we have

$v_s = v_B = -62.2 m/s$ (surface B is now the source, since it reflects the wave, and it is moving towards the receiver)

$v_r = +28.7 m/s$ (surface A is now the receiver, which is moving towards the source)

So, the frequency observed in the source frame is

$f'=(\frac{334 m/s+28.7 m/s}{334 m/s-62.2 m/s})1110 Hz=1481.2 Hz$

(d) 0.225 m

The wavelength of the wave is given by

$\lambda=\frac{v}{f}$

where in this case we have

v = 334 m/s

f = 1481.2 Hz is the apparent in the source frame

So the wavelength is

$\lambda=\frac{334 m/s}{1481.2 Hz}=0.225 m$

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3 years ago