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sweet-ann [11.9K]
3 years ago
10

Do atoms ever touch​

Physics
2 answers:
Mumz [18]3 years ago
8 0

Answer:

nope never

Explanation:

igomit [66]3 years ago
7 0

Answer:

never ever they dont

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You are operating a pwc in an area where swimmers are in the water. When must you slow your pwc to "slow, no wake speed"?.
Lostsunrise [7]

You should slow your pwc to "slow, no wake speed" when within 100 feet of anchored vessels or non-motorized craft.

<h3>What is Slow-no-wake?</h3>

This is the process of operating a personal watercraft at the slowest possible speed.

This helps to maintain steerage which prevents different forms of accident or risks when in motion in the water.

Read more about Slow-no-wake here brainly.com/question/10410716

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4 0
2 years ago
Are fat fish more likely to have broad stripes than thin fish?
maw [93]

yes, just like human skin. The bigger you grown the more your skin stretches, I a fish is bigger their skin will stretch leading to broad stripes.
7 0
3 years ago
Question 2
yarga [219]

Answer:

24.4 m

Explanation:

first we have to calculate how long the cat will be in the air, in vertical direction this is free fall from 4m (poor cat, hope he survived) with acceleration of g=9.81 m/s^2

time = sqrt ( 2 * height / g)

time = sqrt (2 * 4 / 9.81)

time = 0,903 s

then we know his horizontal flight was 22 m long, so ve can calculate verical speed

speed = length / time

speed = 22 m / 0,903 s

speed = 24.363 m

as you are asked to give 3 significant numbers answer is 24,4 m

8 0
3 years ago
In a science museum, a 110 kg brass pendulum bob swings at the end of a 13.9 m -long wire. the pendulum is started at exactly 8:
saw5 [17]

The number of oscillations completed by the pendulum is 2736.

The amplitude of the pendulum is 3.47 m.

The given motion is an underdamped motion. So its frequency will be similar to that of a simple harmonic motion.

The frequency of oscillation is defined as the number of oscillations completed in unit time. It is calculated using the formula.

f=(1/2π)*√(l/g)

where f is the frequency, l is the length of the pendulum, and g is the acceleration due to gravity.

Given the length of the wire l=13.9 m and acceleration due to gravity g=9.8 m/s^2. The frequency of oscillation is:

f=(1/(2*3.14)) * √(13.9/9.8)

f=0.19 Hz (approximately)

Since the pendulum started oscillating at 8:00 am, 4 hours has been passed when it shows 12:00 pm. So time t=4 hours or t=4*3600. Hence t=14400 s. The total number of oscillations is then given by the formula,

n=ft

where n is the number of oscillations.

n=0.19*14400=2736.

In damping motion, the amplitude of the pendulum decreases with time. The amplitude of the pendulum is given by the formula,

A' = A exp (-b*t)

where A' is the amplitude after time t, A is the initial amplitude, b is the damping constant, and t is the time.

Here A=1.2 m, b=0.010 kg/s and t=14400 s.

A' = 1.2 exp (-0.010*14400)

A'=3.47 m (approximately)

Learn more about amplitude.

brainly.com/question/21632362

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5 0
2 years ago
find the gravitational force this shell exerts on a 1.60 kg point mass placed at the distance 5.01 m from the center of the shel
RideAnS [48]

The gravitational force of the shell exerts is 4.25m x 10¯¹² N.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 1.6 kg

m2 = m

R = 5.01 m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 1.6 . m / 5.01²

F = 4.25m x 10¯¹² N

where m is the mass of the shell

For more on gravitational force at: brainly.com/question/19050897

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7 0
1 year ago
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