Answer:
<u>n=-6</u>
Step-by-step explanation:
First, distribute the 5 and the -
5n+20-n-7=-11 now combine like terms,
4n+13=-11 subtract 13 from each side
4n=-24 divide by 4
/4 /4
<u>n=-6</u>
The base is a rectangle and the area of a rectangle is the length times the width.
A line segment formed by the intersection of two faces of a polyhedron.
Answer:
Option (1). (6, 0)
Step-by-step explanation:
The given question is incomplete; here is the complete question.
Which is the ordered pair for the point on the x-axis that is on the line parallel to the given line and through the given point (–6, 10)?
(6, 0)
(0, 6)
(−5, 0)
(0, −5)
Line in orange color is passing through two points (-8, 6) and (4, -4)
Slope of this line = ![\frac{\triangle y}{\triangle x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctriangle%20y%7D%7B%5Ctriangle%20x%7D)
= ![\frac{6+4}{-8-4}](https://tex.z-dn.net/?f=%5Cfrac%7B6%2B4%7D%7B-8-4%7D)
= ![-\frac{10}{12}](https://tex.z-dn.net/?f=-%5Cfrac%7B10%7D%7B12%7D)
= ![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
Other line parallel to this line will have the same slope 'm' = ![-\frac{5}{6}](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D)
Parallel line passes through a point (-6, 10).
Let the other point through which the parallel line passes is (a, b)
Now,
= ![\frac{10-b}{-6-a}](https://tex.z-dn.net/?f=%5Cfrac%7B10-b%7D%7B-6-a%7D)
-5(-a - 6) = 6(10 - b)
5a + 30 = 60 - 6b
5a = -6b + 60 - 30
5a = -6b + 30
a = ![-\frac{6}{5}b+6](https://tex.z-dn.net/?f=-%5Cfrac%7B6%7D%7B5%7Db%2B6)
By satisfying with all the options we find only (6, 0) satisfy this equation.
6 = ![-\frac{6}{5}(0)+6](https://tex.z-dn.net/?f=-%5Cfrac%7B6%7D%7B5%7D%280%29%2B6)
6 = 6
Therefore, (6, 0) is the other point lying on the parallel line.
Option (1) will be the answer.