The maximum height is 144 feet.
The maximum height is the y-coordinate of the vertex. To find the vertex, we first use x = -b/2a. For our information, that is x=-64/2(-16) = -64/-32 = 2.
Now we substitute this into the equation:
y = -16(2²) + 64(2) + 80 = -64 + 128 + 80 = 144
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Given:
Point is T(-3,8).
To find:
The coordinates of T' after 
.
Solution:
We know that, means the figure reflected across the x-axis then reflected across y-axis.
If a figure reflected across x-axis, then
If a figure reflected across y-axis, then
Therefore, the required point is T'(3,-8).
