Can you guys help me? It's due

What is the answer to: -32/40 - 35/40

Mademuasel [1]

Answer:

To subtract fractions, find the LCD and then combine.

Exact Form:

− 67/40

Decimal Form:

− 1.675

Mixed Number Form:

− 1 27/40

Step-by-step explanation:

Please give the brainliest.

6 0

2 years ago

Read 2 more answers

Will give brainliest NEED HELP can some explain how to do this THANKS :D

arlik [135]

Answer:

(x + 13, y + 7)

Step-by-step explanation:

Hello there!

In order to find what the translation rule is, we need to find how much it move to the right/left and up/down

In this case, the line segment VW moved up 7 and to the right by 13

We can get this by checking how far apart the points are

I checked how far apart V and V prime

(V prime is the green V. When a point is primed, its just saying that the point has gone through translation, rotation, dilation, or reflection)

V is 13 units to the left of V prime and 7 units below V prime

This means that, to go from line VW to line V prime W prime, you need to shift the line up 7 units and to the right 13 units

So, the translation rule is (x + 13, y + 7)

*If you don't understand, tell me in the comments, I will try to explain further to your understanding. Thank you, and have a great rest of your day :)*

3 0

2 years ago

HELP PLEASE ILL GIVE U 50 POINTS

klasskru [66]

Answer:

^{3} + 3x

Step-by-step explanation:

^{3} means x cubed.

4 0

3 years ago

Read 2 more answers

you were overcharged $4.52 on your cellphone bill 3 months in a row the cell phone company says that it will add -$4.52 to your

babymother [125]

im pretty sure the last bill you would have been $13.52. but i could be wrong

5 0

3 years ago

The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t

yulyashka [42]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

C

b

C

c

C

d

A

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 0.5 \ in$

Generally the Null hypothesis is $H_o : \mu = 0. 5 \ in$

The Alternative hypothesis is $H_a : \mu \ne 0.5 \ in$

Considering the parameter given for part a

The sample size is n = 15

The test statistics is t = 1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145$

We are making use of this $t_{\frac{\alpha }{2} }$ because it is a one-tail test

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that $t < t_{\frac{\alpha }{2} }$ so the null hypothesis would not be rejected

Considering the parameter given for part b

The sample size is n = 15

The test statistics is t = -1.66

The level of significance $\alpha = 0.05$

The degree of freedom is evaluated as

$df = n- 1$

$df = 15- 1$

$df = 14$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145$

Looking at the value of t and $t_{\frac{\alpha}{2} ,df }$ the we see that t does not lie in the area covered by $t_{\frac{\alpha}{2} , df }$ (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part c

The sample size is n = 26

The test statistics is t = -2.55

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787$

Looking at the value of t and $t_{\frac{\alpha }{2} }$ the we see that t does not lie in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part d

The sample size is n = 26

The test statistics is t = -3.95

The level of significance $\alpha = 0.01$

The degree of freedom is evaluated as

$df = n- 1$

$df = 26- 1$

$df = 25$

Using the critical value calculator at (social science statistics web site )

$t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787$

Looking at the value of t and $t_{\frac{\alpha}{2} }$ the we see that t lies in the area covered by $t_{\alpha , df }$ (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis

6 0

3 years ago