The answer is (3,2). I did this by drawing a graph, inserting the two midpoints you provided, and put in each potential midpoint, finding (3,2) is the only midpoint that connects to the line.
As I understand from the given above, each box when empty weighs 5-2 kg or 3 kg. To determine the total weight of Michael's boxes when empty, we just have to multiply 3 kg by 5. This gives us an answer of 15 kg. Thus, the total mass of Michael's boxes is 15 kg.
Answer:
Step-by-step explanation:
Here you go mate
Step 1
(-5)(5) +5 Equation
Step 2
(-5)(5) +5 Simplify
(-5)(5) +5
Step 3
(-5)(5) +5 Add and multiply them
(-25)+5
answer
-20
Answer:
m(WXY) = 224°
Step-by-step explanation:
Measure of inscribed angle = ½ the measure of intercepted arc
Therefore:
m<C = ½*m(WXY)
112° = ½*m(WXY) (substitution)
Multiply both sides by 2
2*112° = m(WXY)
224° = m(WXY)
m(WXY) = 224°
