1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zanzabum
3 years ago
10

what matrix is a result of m x h enter your answer by filling in the boxes enter any fractions as simplified fractions​

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer:

-32/3 16 -16/3

Step-by-step explanation:

I got it wrong and this was the right answer

You might be interested in
How far is a million inches in a mile? ( There are 5280 feet in 1 mile.)
ella [17]

Answer:

1000000=15.7828283

Step-by-step explanation:

5 0
3 years ago
Find the slope of the line through the pair of points below.<br> (17, -10), (-17, 2)
anastassius [24]

Answer:

use a calculator

Step-by-step explanation:

ur welcome

3 0
3 years ago
When 2251 voters were polled, 52% said they were voting yes on an initiative measure. find the margin of error and an interval t
expeople1 [14]
The margin of error for a sample proportion is given by
z_{\alpha/2}\sqrt{ \frac{p(1-p)}{n} }
where: z_{\alpha/2} is the z score associated with the confidence level, p is the sample prortion and n is the sample size.
We assume a confidence level of 95%, then z_{\alpha/2}=1.96
p = 52% = 0.52 and n = 2251

Therefore, margin of error =
 z_{\alpha/2}\sqrt{ \frac{p(1-p)}{n} }= 1.96\times \sqrt{ \frac{0.52(1-0.52)}{2251} }  \\ = 1.96\times \sqrt{ \frac{0.52(0.48)}{2251} } = 1.96\times \sqrt{ \frac{0.2496}{2251} } \\  = 1.96\times \sqrt{0.000110884} =1.96\times 0.0105 \\ =0.0206=2.1\%

The the interval that is likely to contain the true population proportion is between 49.9% and 54.1%.
5 0
3 years ago
Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up
Artyom0805 [142]

Answer:

In the long run, ou expect to  lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X \sim geom(p = 1/2)

the probability function P can be computed as:

P (X = n) = p(1-p)^{n-1}

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid \sum \limits ^{n}_{i=1} n^2 P(X=n)

\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)

\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2        ∵  X \sim geom(p = 1/2)

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =6

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to  lose $4 per game

3 0
3 years ago
Pleses help me thank you
OLEGan [10]

when solving for y

y = -7x/3-6

 so y does not vary directly with x

 the answer is no

4 0
3 years ago
Other questions:
  • Two ratios that are equivalent to 3: 11
    11·1 answer
  • The mathematical expression 2 V means: <br> what does that mean
    13·1 answer
  • If you run 100 meters in 10 sec, what is your average speed?
    9·1 answer
  • If its width of the perimeter and area is28 square ft what is the length?
    15·1 answer
  • Write your answer in the form y=my+b
    10·1 answer
  • the ratio of boys to girls in a class is 7:5 . there are 36 students in the class. how many students are boys​
    9·2 answers
  • Given: △OKE∼△VDE<br> Prove: EK/EO = ED/EV
    6·1 answer
  • Please help I need an answer ASAP
    5·1 answer
  • Select all equations that have the solution x = 7. 3(x - 5) = 1 + 5(x - 6) 2(x + 7) = 28 6(2x - 1) - 12 = -2(x + 10) 60 = 4(x +
    5·1 answer
  • Please help me out here!
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!