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TEA [102]
3 years ago
5

Round 68.5719758824 to 4 decimal places.

Mathematics
1 answer:
Bingel [31]3 years ago
7 0

Answer:

68.5720

Step-by-step explanation:

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Which of the binomials below is a factor of this trinomial?
8_murik_8 [283]

Answer:

C. x - 4

Step-by-step explanation:

The best way to do this is to first take out GCF

6(x² - x - 12)

Then we factor

6(x - 4)(x + 3)

We can now see our answer.

8 0
3 years ago
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WHOEVER ANSWERS THE FASTEST WINS BRAINIEST ANSWER AND GETS 98 POINTS FOR THIS QUESTION!!!!!! WHO CAN DO IT?
olga nikolaevna [1]

coordinates of b'a'c are

A:(-5,6)

B:(-5,10)

C:(-3,8)

ANswers of ' are

A'(-6,5)

B'(-10,5)

C'(-8,3)

hope this helped

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3 years ago
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Select the ordered pairs that represent solutions to the system of inequalities.Select all that applyAnswer choices:(-6, 3)(-3,
Nadya [2.5K]

We can verify this with the graph

(-6, 3) NO

(-3, 3) NO

(-5, 0) NO

(-4, 2) YES

(0,0) NO

(-6, 6) YES

(-3, -6) NO

(-4.0) YES

the area where the solutions are in the yellow area

5 0
1 year ago
Check all the answers that are more precise than a weight of 200 grams.
Damm [24]

Answer:

amigo mío la respuesta es la letra B

8 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
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