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kirza4 [7]
3 years ago
5

Two boys on bicycles, 45 miles apart, began racing directly toward each other. The instant they started, a fly on the handle bar

of one bicycle started flying straight toward the other cyclist. As soon as it reached the other handle bar it turned and started back. The fly flew back and forth in this way, from handle bar to handle bar, until the two bicycles met.
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Complete question is: Each bicycle have speed 10 mi/h and fly flies at 21 mi/h. How far the fly flies?

Answer:

47.25 mi

Step-by-step explanation:

The relative velocity of the bicycles is 10+10 = 20 mi/h

Time in which the two bicycles meet:

t=\frac{45}{20} = 2.25 h

Distance covered by fly:

d=vt\\d=21mi/h\times 2.25h \\d=47.25 mi

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<h2>Answer:</h2>

42 square units

<h2>Step-by-step explanation:</h2>

For a better understanding, I add an EFGH Rectangle.

The area of EFGH Rectangle = p x l

The area of EFGH Rectangle = 10 x 8

The area of EFGH Rectangle = 80cm²

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x 6 x 4

The area of BHA Triangle = 2 x 6

The area of BHA Triangle = 12cm²

The area of AGD Triangle = 1/2 x a x t

The area of AGD Triangle = 1/2 x 4 x 2

The area of AGD Triangle = 4cm²

The area of CFD Triangle = 1/2 x a x t

The area of CFD Triangle = 1/2 x 2 x 6

The area of CFD Triangle = 6cm²

The area of BEC Triangle = 1/2 x a x t

The area of BEC Triangle = 1/2 x 8 x 4

The area of BEC Triangle = 4 x 4

The area of BEC Triangle = 16cm²

The area of the trapezoid = EFGH Rectangle - (BHA Triangle + AGD Triangle + CFD Triangle + BEC Triangle)

The area of the trapezoid = 80 - (12 + 4 + 6 + 16)

The area of the trapezoid = 80 - 38

The area of the trapezoid = 42cm²

<h3>Conclusion :</h3>

The area of the trapezoid is <u>42 square units</u>

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