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just olya [345]
3 years ago
13

HELP FAST PLS!! Drag each function to correct location on the image. Identify exponential functions.

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
6 0

Answer:

Exponential functions: f(x)=8e^x,f(x)=e^{-3x} and f(x)=20^{\frac{x}{3}}

Non-exponential functions: f(x)=5x^{\frac{3}{7}}, f(x)=4x^3-6x and f(x)=\sqrt{x}+3x

Step-by-step explanation:

The general form of an exponential function is

f(x)=ab^x

where, a is initial value and b is growth factor.

It means the variable term i.e., x must be the exponent . In other words we can say that the variable term must be in the power of constant terms.

We need to check whether the given function is an exponential function or not.

The given function is

f(x)=8e^x

It is an exponential function with initial value 8 and growth factor e≈2.718.

Similarly,

f(x)=e^{-3x} and f(x)=20^{\frac{x}{3}} are exponential functions.

f(x)=5x^{\frac{3}{7}}, f(x)=4x^3-6x and f(x)=\sqrt{x}+3x are non-exponential functions.

slega [8]3 years ago
5 0

Answer:

See the attached

Step-by-step explanation:

An exponential function has the variable in the exponent.

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Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

Multiplying a single row by a scalar scales the determinant by the same amount:

\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}

Then

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}

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2 years ago
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lana [24]

5

the factors of 20 are 1, 2, 4, 5, 10, 20

the factors of 15 are 1, 3, 5, 15

the common factor of 20 and 15 is 5


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3 years ago
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Step-by-step explanation:

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dmitriy555 [2]

Answer:

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Step-by-step explanation:

it would be 70 percent of 140

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