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Softa [21]
4 years ago
9

The teacher separated her class of twenty-eight students into two groups. One group has 4 more than twice as many students as th

e other group. How many students are in each group?
Mathematics
1 answer:
wariber [46]4 years ago
8 0
4+2x = x (x = student in smaller group)

4 + 2x + x = 28 (total # of students)
4+ 3x = 28
3x = 24
x = 8
8 students in the smaller group 
4 + 2(8) = 20 students in the larger group
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Answer:

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Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

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1\text{ sec}=\frac{1}{3600}\text{ hour}

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Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

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