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Softa [21]
3 years ago
9

The teacher separated her class of twenty-eight students into two groups. One group has 4 more than twice as many students as th

e other group. How many students are in each group?
Mathematics
1 answer:
wariber [46]3 years ago
8 0
4+2x = x (x = student in smaller group)

4 + 2x + x = 28 (total # of students)
4+ 3x = 28
3x = 24
x = 8
8 students in the smaller group 
4 + 2(8) = 20 students in the larger group
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Using the grid box, draw a net for a rectangular prism with a length of 8 units, width of 2 units and height of 3 units
prohojiy [21]

Answer:  The answer is in the attached figure.


Step-by-step explanation:  We are given to draw a net for a rectangular prism  of length 8 units, width 2 units and height 3 units.

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As given in the question, a rectangular prism ABCDEFGH is drawn in the attached figure, where length is 8 units, width is 2 units and height is 3 units.


8 0
3 years ago
The triangles are similar by??
allsm [11]

the SAS similarity theorem

8 0
2 years ago
What is 20% of $4999.99
Lynna [10]

Answer:

999.99

Step-by-step explanation:

I just got took the test it is correct

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8 0
2 years ago
Read 2 more answers
Determine whether (3, 2) and (2, - 1) are solutions to the equation – 3x + y = - 7.
Leona [35]

Answer:

D

Step-by-step explanation:

plug in (3,2) to see if it's a solution:

A) does -3(3) + 2 equal -7?    yes

B) since 'A' is a solution then 'B' cannot be the answer

C) since (3,2) is a solution then 'C' cannot be the answer

plug in (2,-1) to see if it's a solution:

plug in (2,-1) to see if it's a solution:

-3(2) - (-1) equal -7?   no, it equals -5

only (3,2) is a solution so the answer is D

8 0
2 years ago
How does it factor out as that?
eimsori [14]
To factor out you have to think what multiples to AC and adds to B.

Ax^2+Bx+C

So... for this problem AxC=1x-24 or -24

B is -2.

So what two numbers multiply to -24: -3x8, -8x3, -4x6, -6x4, -2x12, -12x2.

Out of these, which adds to -2: -6+4=-2.

So the factors are (d-6)(d+4)

OR the longer way, which you really only use if A is not equal to 1.

Use the terms above and then rewrite the equation with two middle terms: d^2+4d-6d-24

Group the terms by using addition: (d^2+4d)+(6d-24)

Find what they have in common and factor it out. For the first, it's d. They both have d. So: d(d+4)
To check this, distribute the d. It should equal the first set lf parenthesis.

For the second, they have a number in common. 6 is a multiple of 24 so you can take that out: -6(d+4)

If the terms inside the parenthesis are the same, that's good. It means we can pair the insides and the outsides together to form the factors.

The two terms outside the parenthesis: d, -6 group together and become (d-6)

The inside terms stay the same: (d+4)

(d-6)(d+4)

Again, this is the longer way and no necessary for a problem like this. But if it was 2d^2, then this would be perfecf.




6 0
2 years ago
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