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Schach [20]
3 years ago
15

Kayla wants to find the width, AB, of a river. She walks along the edge of the river 100 ft and marks point C. Then she walks 22

ft further and marks point D. She turns 90° and walks until her location, point A, and point C are collinear. She marks point E at this location, as shown.
Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0
You did not give me B, so I cannot help you with this question.
musickatia [10]3 years ago
5 0

Answer:

Given data

edge of the river=100 ft

angle=90

Width of AB=100+22sin90

Width of AB=122 ft

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If the area of an equilateral triangle is 9root3 cm square find its side​
kobusy [5.1K]

Answer:

6 cms.

Step-by-step explanation:

If the side of an equilateral triangle is 2x cm then its height is  √3x and its base is 2x.

Area = 1/2 * base * height

9√3 = 1/2 * 2x * √3x    

9√3 = x * √3x

9 = x^2

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So length of each side = 2*3 = 6.

x = 9

7 0
3 years ago
A BASKETBALL PLAYER MAKES A BASKET THROUGH A TEN FOOT HIGH BASKET FROM 20 FEET AWAY. IF THE SHOOTER RELEASES THE BALL FROM 8 FEE
mixas84 [53]

Answer:

The vertical velocity of the ball when released = 10.81 m/s

The vertical velocity of the ball in the basket = 8.81 m/s

Step-by-step explanation:

The given parameters are;

The height of the basket = 10 feet

The horizontal location of the shooter from the basket = 20 feet

The height from which the shooter releases the ball = 8 feet

The horizontal velocity of the ball = 10 ft/s

Therefore, we have;

Time, t = Horizontal distance/(Horizontal velocity)

t = 20/10 = 2 seconds

The vertical velocity is given as follows;

s = u·t - 1/2·g·t²

Where;

u = The vertical velocity

s = The height above the initial height from which the ball is released

s = y - y₀

Where;

y = The final height of the ball in the calculation = The height of the basket = 10 foot

y₀ = The initial height from which the ball is released = 8 feet

∴ s = 10 - 8 = 2 feet

g = The acceleration due to gravity = 9.81 m/s²

Substituting gives;

2 = u × 2 - 1/2 × 9.81× 2²

u = (2 + 1/2 × 9.81× 2²)/2 = 10.81 m/s

The vertical velocity of the ball when released = 10.81 m/s.

The vertical velocity of the ball in the basket is given by the following relation;

v² = u² - 2·g·s

v² = 10.81² - 2×9.81×2 = 77.6161

v = √(77.6161) = 8.81 m/s

The vertical velocity of the ball in the basket = 8.81 m/s

7 0
3 years ago
A triangle has an area of 14 square units. Its height is 7 units. What is the length of its base?
navik [9.2K]
The base should be 4. 
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motikmotik

Answer:

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Step-by-step explanation:


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Answer:

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or

if you are above 11th standard

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