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Schach [20]
3 years ago
15

Kayla wants to find the width, AB, of a river. She walks along the edge of the river 100 ft and marks point C. Then she walks 22

ft further and marks point D. She turns 90° and walks until her location, point A, and point C are collinear. She marks point E at this location, as shown.
Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0
You did not give me B, so I cannot help you with this question.
musickatia [10]3 years ago
5 0

Answer:

Given data

edge of the river=100 ft

angle=90

Width of AB=100+22sin90

Width of AB=122 ft

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Write an equation for the line parallel to the given line that contains C.
lyudmila [28]

ANSWER

y= - 4x + 18

EXPLANATION

The given line has equation;

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The equation of this line is in the form:

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We substitute the slope and the point:

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y-6= - 4(x-3)

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6 0
3 years ago
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Crazy boy [7]

Answer:

1

8

4

−

3

3

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2

3

+

2

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1

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x

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10

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6

18x4−3x3−2x3+x2−10+6

1

8

4

−

3

3

−

2

3

+

2

−

4

18

x

4

−

3

x

3

−

2

x

3

+

x

2

−

4

18x4−3x3−2x3+x2−4

2

Combine like terms

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1

8

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5

3

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2

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4

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7 0
3 years ago
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leva [86]

Step-by-step explanation:

for given cone:

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\therefore \: l =  \sqrt{ {h}^{2}  +  {r}^{2} }  \\  =  \sqrt{ {3}^{2} +  {3}^{2}  }  \\  =  \sqrt{9 + 9}  \\  =  \sqrt{2 \times 9}  \\   \therefore \: l= 3 \sqrt{2}  \: ft \\  \\ total \: surface \: area \: of \: cone \\  = \pi \: r(l + r) \\  = 3.14 \times 3(3 \sqrt{2}  + 3) \\  = 9.42 \times 3( \sqrt{2}  + 1) \\  = 28.26 \times (1.414 + 1) \\  = 28.26 \times 2.414 \\  = 68.21964 \\  \approx \: 68.2 \:  {ft}^{2}

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