3.
3x15=45
3x8=24.
Hope I helped!
Answer:
y = -3/8(x + 2)^2 + 8
Step-by-step explanation:
vertex form is
y = a(x - b)^2 + c where a is a constant and (b,c) is the vertex.
The maximum is at (-2, 8) because x 8 = height and x =-2 is equn. of symmetry
So here we have
y = a(x - (-2))^2 + 8
y = a(x + 2)^2 + 8
Now at the point (-6, 2):
2 = a(-6+2)^2 + 8
2 = 16a + 8
16a = -6
1 = -3/8.
So our equation is y = 3/8(x + 2)^2 + 8
Answer:
see attached diagram
Step-by-step explanation:
A dilation with a scale factor of 
centered at the origin has a rule:
Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
