The gravitational potential energy has the formula:
PE = mgh
where PE is in joules
m is the mass of the object in kg
g is the acceleration due to gravity
h is the height in m
since you did not give the value of h, i cannot fully answer your quesstion.
PE = (58/1000 kg) (9.81m/s2) h
PE = 0.57h
just substitute the value of h in the equation
Answer:
Explanation:
Given that,
Initially, the spaceship was at rest, u = 0
Final velocity of the spaceship, v = 11 m/s
Distance accelerated by the spaceship, d = 213 m
We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.
So, the acceleration experienced by the occupants of the spaceship is 
.
A car acting as an object in front of a biconvex lens between F and 2 F on the object side of the lens. There is a light ray parallel to the principal axis that is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect below the x axis further than 2 F away from the lens and farther from the principal axis than the object is tall.
<u> The image produced by the lens is (b) inverted and real</u>
Explanation:
A real image occurs where the rays converge.
Real images can be produced both by the concave mirrors or converging lenses, but the condition is that the object of consideration is always placed far away from the mirror or the lens than the focal point, and thus the real image produced is inverted.
A car acting as an object in front of a biconvex lens between F and 2 F on the object side of the lens. There is a light ray parallel to the principal axis that is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect below the x axis further than 2 F away from the lens and farther from the principal axis than the object is tall.
<u> The image produced by the lens is (b) inverted and real</u>
