The answer to your question I think it is A but I’m not 100%
Answer:
Explanation:
Angular speed of the motion ( SHM )
ω = √k/m
= √(580/.23 )
= 50.20 radian /s
a ) Rate of doing work
= power = force x velocity
At the equilibrium position force becomes zero so
rate of doing work is zero.
b )
If a be the amplitude
1/2 k a² = 170
a = .7655 m
kinetic energy at equilibrium = 1/ 2 m v₀²
1/ 2 m v₀² = 170
.5 x 23 v₀² = 170
v₀ = 3.84 m /s which is the maximum velocity.
Given x = .66 where rate of doing work is to be calculated.
Force at x = ω² x
= 50.20² x .66 =
= 1663.22 N
Velocity v = v₀ √( a² - x² )
= 3.84 √( .7655² - .66 )
= 3.84 x .387
= 1.486 m/s
power = force x velocity
= 1663.22 x 1.486
= 2471.55 W .
The distance they covered was 17 Km. Not sure that their displacement was though sorry.
Answer:
read this it might help some
When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.
Explanation:
An eclipse is a phenomenon of an astronomical object being obscured by something. In this case, it is the Moon that is being obscured from sunlight by Earth's shadow. Answer is D.