Which the answer It's science

When the voltage is high, 100v, how does the filament appear?

Nat2105 [25]

when voltage is high say 100V than the light will be a lot dimmer than design because the light is usually designed to be operated at 240V . If the supply voltage to the bulb is 100V, the filament dissipates 34.7W power and thus the temperature of the filament will be less and hence the bulb does not produce so much light .

8 0

3 years ago

At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g

Strike441 [17]

Answer:

31.905 ft/s²

Explanation:

Given that

Mass of the pilot, m = 120 lb

Weight of the pilot, w = 119 lbf

Acceleration due to gravity, g = 32.05 ft/s²

Local acceleration of gravity of found by using the relation

Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)

119 = 120 * a/32. 174

119 * 32.174 = 120a

a = 3828.706 / 120

a = 31.905 ft/s²

Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²

3 0

3 years ago

When your sled starts down from the top of a hill, it hits a frictionless ice slick that extends all the way down the hill. At t

Blababa [14]

Answer:

Explanation:

Given that,

Height of hill is 50m

Coefficient of friction is μ=0.62

Energy is conserved, then

K.E at the bottom of the hill is equally to P.E at the top of the hill

½mv²=mgh

Mass cancel out

½v²=gh

v²=2gh

v=√2gh

Since g=9.81 and h=50

v=√2×9.81 ×50

v=31.32m/s

This is the initial speed at the bottom of the hill

At the bottom of the hill 3 forces are acting on the body

1. Weight,

2. Normal

3. Frictional force

Now taking newton law of motion

ΣF = ma.

Along y axis, since the body is not moving in y direction, they acceleration along y is 0m/s²

ΣFy = 0

N-W=0

N=W

Since weight =mg

N=W=mg

Using law of friction, Fr=μN

Therefore,

Fr=μmg

Applying Newton law to the x-direction

ΣFx = ma

Fr=ma,

Since Fr=μ mg

μ mg=ma

a=μg

Given that μ=0.62 and g=9.81

a=0.62×9.82

a=6.076m/s²

Since we have acceleration, we can use any of the equation of motion to find distance travel

v²=u²-2gS, . this is due that the box is decelerating and it comes to a halt and this show that final velocity v=0m/s

Then,

0²=31.32²-2×9.81 ×S

-31.32² =-2×9.81×S

S=31.32²/(2×9.81)

S=50.05m

The sled will travel a distance of 50.1m once it reach the bottom

5 0

3 years ago

A rigid tank initially contains 3kg of carbon dioxide (CO2) at a pressure of 3bar.The tank is connected by a valve to a friction

marissa [1.9K]

Answer:

Part a: The total amount of energy transfer by the work done is 54.81 kJ.

Part b: The total amount of energy transfer by the heat is 54.81 kJ

Explanation:

Mass of Carbon Dioxide is given as m1=3 kg

Pressure is given as P1=3 bar =300 kPA

Volume is given as V1=0.5 m^3

Pressure in tank 2 is given as P2=2 bar=200 kPa

T=290 K

Now the Molecular weight of $CO_2$ is given as

M=44 kg/kmol

the gas constant is given as

$R=\frac{\bar{R}}{M}\\R=\frac{8.314}{44}\\R=0.189 kJ/kg.K$

Volume of the tank is given as

$V=\frac{mRT}{P_1}\\V=\frac{3 \times 0.189 \times 290}{300 }\\V=0.5481 m^3$

Final mass is given as

$m_2=\frac{P_2V}{RT}\\m_2=\frac{200\times 0.5481}{0.189\times 290}\\m_2=2 kg$

Mass of the CO2 moved to the cylinder

$m=m_1-m_3\\m=3-2=1 kg$

The initial mass in the cylinder is given as

$m_{(cyl)_1}=\frac{P_{(cyl)_1}V_1}{RT}\\m_{(cyl)_1}=\frac{200\times 0.5}{0.189 \times 290}\\m_{(cyl)_1}=1.82 kg$

The mass after the process is

$m_{(cyl)_2}=m_{(cyl)_1}+m\\m_{(cyl)_2}=1.82+1\\m_{(cyl)_2}=2.82\\$

Now the volume 2 of the cylinder is given as

$V_{(cyl)_2}=\frac{m_{(cyl)_2}RT}{P_2}\\m_{(cyl)_2}=\frac{2.82\times 0.189\times 290}{200}\\m_{(cyl)_1}=0.774 m^3$

Part a:

So the Work done is given as

$W=P(V_2-V_1)\\W=200(0.774-0.5)\\W=54.81 kJ$

The total amount of energy transfer by the work done is 54.81 kJ.

Part b:

The total energy transfer by heat is given as

$Q=\Delta U+W\\Q=0+W\\Q=54.81 kJ$

As the temperature is constant thus change in internal energy is 0.

The total amount of energy transfer by the heat is 54.81 kJ

7 0

3 years ago

Parallel perpendicular or neither y=6x-3 y=-1/6x + 7

Mariana [72]

Answer:

90 i think

Explanation:

4 0

3 years ago