Which the answer It's science

One way in which elements differ from each other is the structure of the electron cloud in each element’s atoms. In an electron

Brums [2.3K]

The electron cloud is split up in 3 areas.

1) Inner Electron Cloud
2) Outer Electron Cloud
3) Valence Electrons

Your inner cloud is the electrons CLOSEST to the nucleus.
Your outer cloud is the electrons in the MIDDLE of the Inner and Valence.
Your valence electrons are the OUTER LAYER of electrons. These electrons are important to bonding, and also are what decide where on the periodic table of elements. For example:

197
Au
79

This element is GOLD. It has 1 valence, therefor it is where it is in the period. Ionization could change this number however.

5 0

4 years ago

Read 2 more answers

- A cannon of 2000 kg fires a shell of 10 kg at

fgiga [73]

1) -0.5 m/s

We can solve the first part of the problem by using the law of conservation of momentum. In fact, the total momentum of the cannon - shell system must be conserved.

Before the shot, both the cannon and the shell are at rest, so the total momentum is zero:

$p=0$

After the shot, the momentum is:

$p=MV+mv$

where

M = 2000 kg is the mass of the cannon

m = 10 kg is the mass of the shell

v = 100 m/s is the velocity of the shell (we take as positive the direction of motion of the shell)

V = ? is the velocity of the cannon

Since momentum is conserved, we can write

$0=MV+mv$

And solving for V, we find the velocity of the cannon:

$V=-\frac{mv}{M}=-\frac{(10)(100)}{2000}=-0.5 m/s$

where the negative sign indicates that the cannon moves in the direction opposite to the shell.

2) 0.5 m

The motion of the cannon is a uniformly accelerated motion, so we can solve this part by using suvat equation:

$v^2-u^2=2as$

where

v is the final velocity of the cannon

u = 0.5 m/s is the initial velocity of the cannon (now we take as positive the initial direction of motion of the cannon)

$a=-0.25 m/s^2$ is the deceleration of the cannon

s is the distance travelled by the cannon

The cannon will stop when v = 0; substituting and solving the equation for s, we find the minimum safe distance required to stop the cannon:

$s=\frac{v^2-u^2}{2a}=\frac{0-0.5^2}{2(-0.25)}=0.5 m$

7 0

4 years ago

Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resisto

Ganezh [65]

Answer:

Explanation:

A and B are in series , Total resistance = Ra + Rb

This resistance is in parallel with single resistor C

Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]

Now this combination is in series in single resistance D .

Total resistance = Rd + Re

= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }

5 0

3 years ago

the star of Africa, a diamond in the royal scepter of the British crown jewels, has mass of 530.2 carats, where 1 carat = 0.20 g

QveST [7]

Given:
Mass of the diamond = 530.2 carats
1 carat = 0.20 g = 0.20 x 10⁻³ kg
1 kg = 2.21 lb

Therefore the mass of the diamond is
$(530.2 \, carats)*(0.20 \times 10^{-3} \, \frac{kg}{carat})*(2.21 \, \frac{lb}{kg}) = 0.2343 \, lb$

Answer: 0.2343 lb

6 0

3 years ago

Two out of phase loudspeakers are some distance apart. A person stands 4.50 m from one speaker and 3.80 m from the other. What i

Contact [7]

Answer:

The third lowest frequency is 1489.27 Hz.

Explanation:

Given that,

Distance of person from one speaker= 4.50 m

Distance of person from the other = 3.80 m

The longest wavelength is the shortest frequency.

We need to calculate the difference between the speakers