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3 years ago

The initial speed of a body is 3.28 m/s. What is its speed after 2.32 s if it accelerates

1 answer:

6 0

Final velocity = initial velocity + acceleration * time

v = u + at

v = 3.28 + 2.32 * 2.08

v = 3.28 + 4.83

v = 8.11 m/s

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PLEASE HELP!!!! OFFERING 99 POINTS!!

Nitella [24]

The Gravitational PE (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleration (g), which is 9.81 m/s^2 on Earth’s surface.

so U = mgh = 9.81mh on earth

mass of the car = 50.0 grams = 0.05kg

height, h:

Hill 1 = 90.0 cm = 0.9m,

Hill 2 = 65.0 cm = 0.65m,

Hill 3 = 20.0 cm = 0.2m

substitute into eqn U = mgh

U @ top of Hill 1 = 0.05*9.81*0.9 = 0.4415J

U @ top of Hill 2 = 0.05*9.81*0.65 = 0.3188J

U @ top of Hill 3 = 0.05*9.81*0.2 = 0.0981J

difference in Gravitational Potential Energy from the top of Hill 1 to the top of Hill 3 = 0.4415 - 0.0981

= 0.3434J where J is the unit for energy, Joules

7 0

3 years ago

Read 2 more answers

Find the energy released in the fission reaction¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n) The atomic masses of the fission product

ikadub [295]

Fission reaction is given

¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n)

The atomic masses of the fission products are 97.912735 u for ⁹⁸₄₀Zr and 134.916450 u for ¹³⁵₅₂Te. Hence, the energy released in fission reaction is 191.715 MeV.

How to find the energy released in the given fission reaction?

We know, that the atomic mass of the elements are as follows:

⁹⁸₄₀Zr - 97.9120u

¹³⁵₅₂Te - 134.9087u

²³⁵₉₂U - 235.0483923u
n = 1.008665u

In order to find the mass difference, we will calculate the initial mass and the mass of products.

The equation for the reaction:

n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3n

Mass of initial reagents is 1.008665u + 235.0483923u = 233.052588u

Product of the reagents is 97.9120u + 134.9087u + 3(1.008665u) = 235.846773u

Now, using the formula of

$E=(\triangledown m)c^2$

$E=(0.205815u)\frac{931.494MeV/c^2}{u} c^2=191.715MeV$

Hence, the energy released in fission reaction is 191.715 MeV.

To learn more about fission reactor, refer to:

brainly.com/question/23276812

#SPJ4

4 0

2 years ago

19. A small dog is trained to jump straight up a distance of 1.2 m. How much kinetic energy does the 7.2-kg dog need to jump thi

vova2212 [387]

How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m?
Answer:

85 Joule (approx)

Explanation:

Potential energy at highest point

P.E = mgh = 7.2 kg × 9.8 m/s2×1.2 m≈85 Joule

4 0

4 years ago

Need examples of a science fair project, this project need to require some sort of data (any type of science)

Natasha_Volkova [10]

Put vinegar in a water bottle with no water, fill a balloon with baking soda, without pouring the baking soda in the vinegar put the balloon on the water bottle, then lift it so the baking soda goes in the vinegar, this will blow up the balloon

4 0

3 years ago

How much electrical energy is used by a 75 W laptop that is operating for 12 minutes?

Liono4ka [1.6K]

"1 watt" means 1 joule of energy per second.

75 W means 75 joules/sec .

Energy = (75 Joule/sec) x (12 min) x (60 sec/min)

Energy = (75 x 12 x 60) (Joule-min-sec / sec-min)

Energy = 54,000 Joules

7 0

3 years ago