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3 years ago

Gracie can purchase 5 oranges for $4 but she only wants one what is the cost of one orange

Mathematics

1 answer:

vladimir2022 [97]3 years ago

8 0

The cost of one orange is $1.25
what you do is you divide 5 by 4 so 5 divided by 4= 1.25
hope this helps!

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Help with this please

Svet_ta [14]

The answer to the question is D

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3 years ago

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Have I worked out the following right:

Studentka2010 [4]

Answer: I think the answer is 173.25

Step-by-step explanation:

To find that you have to times them.

15.0*11.55 = 173.25

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3 years ago

A cube has a surface area of 486 cm2. What is the side length ?

astraxan [27]

A Cube, has all equal sides, namely, the length, width and height
are all equal to each other

so.. notice the picture added here
you have really, 6 squares, stacked up to each other at the edges

so...what is the Area of one of those squares?
well, if the sides are equal, let's say the side is "x" long, then
the Area is $x\cdot x \implies x^2$

well, you have 6 of those squares, thus $\bf \textit{surface area of a cube}=
\begin{cases}
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)+\\
(x\cdot x)\\
 --------------\\
 x^2+x^2+x^2+x^2+x^2\\
6x^2
\end{cases}
\\\\
\textit{we know the Area is }486\ cm^2\qquad thus
\\\\
\textit{surface area}=6x^2\implies 486=6x^2$

solve for "x", to get one side's length

3 0

3 years ago

✨PLEASE HELP✨ DUE SOON

mestny [16]

Hey :) it’s (2,5) it’s C !!

6 0

3 years ago

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A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

7 0

3 years ago