Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
<h3>How many sweets does Nathan gets?</h3>
Given that, Nathan shares out 12 sweets, he gives Yasmin 1 sweet for 3 sweets he buys.
Let the sweet be represented by x
For each x sweet for Yasmin, Nathan gets 3x sweets
Hence
x + 3x = 12
We solve for x
4x = 12
x = 12/4
x = 3
Hence;
Yasmin gets x sweet = 3
Nathan gets 3x sweets = 3 × 3 = 9
Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
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Answer:
1. 14/15
2. 5 7/8
3. 81.25%
Step-by-step explanation:
1. (fraction) 7/9 divided by 5/6 (fraction)
7/9 ÷ 5/6 =
= 7/9 * 6/5
= (7 * 6)/(9 * 5)
= 42/45
= 14/15
2.
1 3/8 + 4 1/2 =
= 1 + 3/8 + 4 + 1/2
= 1 + 4 + 3/8 + 4/8
= 5 + 7/8
= 5 7/8
3.
percent = part divide by whole times 100
13/16 * 100 =
= 81.25%
Answer:
a
The estimate is 
b
Method B this is because the faulty breaks are less
Step-by-step explanation:
The number of microchips broken in method A is 
The number of faulty breaks of method A is 
The number of microchips broken in method B is 
The number of faulty breaks of method A is 
The proportion of the faulty breaks to the total breaks in method A is


The proportion of the faulty to the total breaks in method B is

For this estimation the standard error is

substituting values


The z-values of confidence coefficient of 0.95 from the z-table is

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as
![K = [p_1 - p_2 ] \pm z_{0.95} * SE](https://tex.z-dn.net/?f=K%20%3D%20%5Bp_1%20-%20p_2%20%5D%20%5Cpm%20z_%7B0.95%7D%20%2A%20SE)
substituting values
![K = [0.08 - 0.07 ] \pm 1.96 *0.0186](https://tex.z-dn.net/?f=K%20%3D%20%5B0.08%20-%200.07%20%5D%20%5Cpm%201.96%20%2A0.0186)

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

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Step-by-step explanation:
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