Answer:
A sample of 1068 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?
We need a sample of n.
n is found when M = 0.03.
We have no prior estimate of
, so we use the worst case scenario, which is 
Then






Rounding up
A sample of 1068 is needed.
Answer: Yes, this is true but it can be a different answer.
The slope is 4. It's right there in the problem. The equation underneath that is y=mx + b. M, in this case 4 or 4/1 is the slope. And 5 is the y intercept or where the line crosses the y axis.
Answer:
its 72
Step-by-step explanation:
hope this helps