5x + 3y = - 53
the equation of a line in ' slope- intercept form ' is y = mx + c
where m is the slope and c the y-intercept
rearrange 3x - 5y = - 15 into this form to obtain m → (subtract 3x from both sides)
- 5y = - 3x - 15 → divide all terms by - 5 )
y = 
x + 3 → in slope-intercept form with m =
given a line with slope m then the slope m₁ of a line perpendicular to it is
m₁ = - 
= - 1 ÷ = - 
partial equation is y = - x + c
to find c substitute ( - 7, - 6) into the partial equation
- 6 = 
+ c ⇒ c = - 6 - = - 
y = - x - → in slope intercept form
multiply all terms by 3
3y = - 5x - 53 → ( add 5x to both sides )
5x + 3y = - 53 → in standard form
Answer:
The answer should be 150 x .20 = 30m/s
Answer:
The probability is 1/9
Step-by-step explanation:
The probability of rolling a 5 the first time is 1/6
The probability of rolling a number greater than 2
Numbers greater than 2 are 3, 4, 5, 6
So the probability of rolling a number out of these four is 4/6
So the probability of rolling a five for the first time and the probability of rolling a number greater than 2 the second time will be
1/6 * 4/6 = 4/36 = 1/9
Answer:
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D9%269%5C%5C-3%262%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
To add matrices, we add the corresponding components.
The given matrices is
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D)
We add the corresponding components to get;
![\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}3+6&9+0\\5+-8&-2+4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%269%5C%5C5%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%260%5C%5C-8%264%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%2B6%269%2B0%5C%5C5%2B-8%26-2%2B4%5Cend%7Barray%7D%5Cright%5D)
We simplify to get:
It would be C because a coefficient is always with a variable and 6 is with a variable which makes it a coefficient
Hope this helps
Have a great day/night
