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2 years ago

What is 12.5% As a fraction

Mathematics

2 answers:

tatiyna2 years ago

7 0

12.5/100

This can be simplified to:

125/1000

wel2 years ago

4 0

18/12 is the answer to that

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How do you do n x,y table for y=-x-5

eimsori [14]

Thanks for the free points

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3 years ago

Does anyone know how to simplify this -4i(2+3i)???

Artist 52 [7]

Answer:

Step-by-step explanation:

-4i(2+3i)

-8i-12i

3 0

2 years ago

Read 2 more answers

If the equation y² - (K-<br>2y + 2k +1 = 0<br>with equal roots find the value of k

777dan777 [17]

Answer:

y² - (K- 2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

8 0

2 years ago

Why equals 3/4 X -12 and why equals negative 4X - 31

Helga [31]

Answer:

(x, y) = (-4, -15)

Step-by-step explanation:

Perhaps you want the solution to ...

y = 3/4x -12

y = -4x -31

Equating the two expressions for y gives ...

3/4x -12 = -4x -31

3/4x = -4x -19 . . . . . add 12

3x = -16x -76 . . . . . multiply by 4

19x = -76 . . . . . . . . . add 16x

x = -76/19 = -4 . . . . divide by 19

y = (3/4)(-4) -12 = -15 . . . . use the first equation to find y

The solution to this system of equations is ...

(x, y) = (-4, -15)

8 0

3 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

2 years ago