<span>4/9 is the fraction for 0.4 repeating.</span>
For this case we have:
a = 30 cm
c = 16 cm
We look for the length of the diagonal:
d = x + y
Where,
For x:
a ^ 2 = x ^ 2 + x ^ 2
x = a / root (2) = 30 / root (2) = 21.2132 cm
For y:
c ^ 2 = y ^ 2 + y ^ 2
y = c / root (2) = 16 / root (2) = 11.3137 cm
The diagonal is:
d = x + y
d = 21.2132 + 11.3137
d = 32.5269 cm
Then, the height is:
h = h1 + h2
For h1:
h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
h1 = 15 cm
For h2:
h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
h2 = 8 cm
Finally:
h = h1 + h2
h = 15 + 8
h = 23 cm
Then, the area is:
A = (1/2) * (a + c) * (h)
A = (1/2) * (30 + 16) * (23)
A = 529 cm ^ 2
Answer:
the area of an isosceles trapezoid is:
A = 529 cm ^ 2
Answer:
X=-2.5
4-(2x+4)=5
cancel out 4 and -4
-2x=5
-x=2.5
x=2.5
hope this helps man :)
Step-by-step explanation:
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. The measure of an inscribed angle is always half the measure of the arc it forms. Since angle ACB forms arc AB with a measure of 100 degrees, the measure of angle ACB will be equal to .
2. Relating to problem 1, both inscribed angles marked in the figure form the same arc. All inscribed angles forming the same arc will have the same measure. Therefore, the measure of angle GEF is equal to .