3/2x-7=-11
We move all terms to the left:
3/2x-7-(-11)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
3/2x+4=0
We multiply all the terms by the denominator
4*2x+3=0
Wy multiply elements
8x+3=0
We move all terms containing x to the left, all other terms to the right
8x=-3
x=-3/8
x=-3/8
Answer:
IT's d!!!!!
Step-by-step explanation:
| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
All that is needed is for you to graph the points and if they form a line, they will be collinear. If not, they will not be collinear.
Don’t fall for this it’s fake
