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Effectus [21]
3 years ago
9

2/9 of the students in a school are in sixth grade.

Mathematics
2 answers:
IRISSAK [1]3 years ago
5 0

There are 20 students in sixth grade

Step-by-step explanation:

  • Step 1: Find the number of sixth-graders in the school.

Total number of students = 90

Number of sixth-graders = 2/9 of total students

⇒ Number of 6th graders = 2/9 × 90 = 20 students

Alekssandra [29.7K]3 years ago
4 0

Answer:

20

Step-by-step explanation:

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Find all the critical values
Natalija [7]
              y - 3
g(y) = ------------------
            y^2 - 3y + 9

To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
     
             (y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
                    (y^2 - 3y + 9)^2

Note carefully:  The denom. has no real roots, so division by zero is not going to be an issue here.  

Simplifying the denominator of the derivative, 

(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)  =>  y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
                                                         -y^2 + 6y

Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6.  These are your critical values.  You may or may not have max or min at one or the other.
6 0
3 years ago
How do you substitute x+y=2 3x+2y=5
Monica [59]
Here's how you solve this.  So, x+y=2, right?  Let's isolate x.  x+y-y=2-y.  x=2-y.  NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y!  3x+2y=5.  3(2-y)+2y=5.  (3*2)+(3*-y)+2y=5.  6+(-3y)+2y=5.  6+(-y)=5.  6+(-y)-6=5-6.  -y=-1.  -y/-1=-1/-1.  y=1.

So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2.  x+1=2.  x+1-1=2-1.  x=1.  1+1=2, so that works; let's check the other equation.  3(1)+2(1)=5.  3+2=5.  5=5.  That's correct!

Answer: x=1, y=1
4 0
3 years ago
Read 2 more answers
A circle has 9 times the area of another circle. If the radius of the larger circle is 27 meters, find the radius of the smaller
hoa [83]

Answer:

Step-by-step explanation:

5 0
3 years ago
I don’t understand this problem
Rina8888 [55]

Answer:

Standard Deviation, σ = 6.5828058860438

Step-by-step explanation:

<u>Data Set:</u> 20, 11, 27, 13, 29, 20

The total numbers in the data set

Count, N = 6

The sum is all values in the data set is added up

20 + 11 + 27 + 13 + 29 + 20

Sum, Σx: 120

The mean is the sim / N

Mean, μ: 20

7 0
1 year ago
Is the following function even, odd or neither? f(x)=x^3 +4x
erica [24]

Answer:

D, neither

Step-by-step explanation:

to determine whether a function is even, odd or neither, we need to know what it means

an even function is symmetric with respect to the y-axis

an odd function is symmetric with respect to the origin

to solve an equation to see if its even or odd, we would need to substitute <em>x</em> in the equation for <em>-x</em>.

in an even function when we substitute f(-x), it should be equal to to f(x)

in an odd function when we substitute f(-x), it should be equal to -f(x)

so lets test the function given to see if its even

f(x) = x³ + 4x

f(-x) = (-x)³ + 4(-x)

f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to the orignal function, we see that f(-x) = x³ - 4x is not even as we did not get the same output as the original function

now we should test to see if its odd. we have already seen what f(-x) is, now lets try -f(x) and compare it to f(-x) and f(x)

-f(x) = -(x³ + 4x) -->

-f(x) = -x³ - 4x ≠ f(-x) = x³ - 4x

f(-x) = x³ - 4x ≠ f(x) = x³ + 4x

comparing this to f(x) and f(-x), we see that it not odd as we did not get the same output

so the answer is D, neither even nor odd

6 0
3 years ago
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