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Effectus [21]
3 years ago
9

2/9 of the students in a school are in sixth grade.

Mathematics
2 answers:
IRISSAK [1]3 years ago
5 0

There are 20 students in sixth grade

Step-by-step explanation:

  • Step 1: Find the number of sixth-graders in the school.

Total number of students = 90

Number of sixth-graders = 2/9 of total students

⇒ Number of 6th graders = 2/9 × 90 = 20 students

Alekssandra [29.7K]3 years ago
4 0

Answer:

20

Step-by-step explanation:

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F(x)=-4x - 10 find x when f(x)=10
BARSIC [14]

Answer:

-40

Step-by-step explanation:

f(10)=-4(10)

f(10)=-40

4 0
3 years ago
Nancy sold a house for $225,900 and earned 4% commission. How much did Nancy earn for the sale of this house?
timurjin [86]

Answer:

$9,036.00

Step-by-step explanation:

225900×.04

4%= .04

4. Move decimal twice to the left=.04

3 0
3 years ago
A 14 foot is cut into two pieces so that one piece is 3 feet longer than twice the shorter piece
DochEvi [55]
To answer the question above, let x be the shorter one of the pieces. With the variable, we can express the longer piece as 2x + 3. Based on the given, the sum of the lengths of these pieces should sum up to 14 ft. 

                                        2x + 3 + x = 14 ft, x = 3 2/3 ft

Substituting this value for the longer piece, we get 10 1/3 ft. Thus, the lengths of the pieces are 3 2/3 ft and 10 1/3 ft. 

3 0
3 years ago
NEED HELP ASAP!!Approximately 10% of Wunderlich's population is left-handed. If the school has a population of 1,200 students, h
Alexxx [7]

Answer:

B. 120

Step-by-step explanation:

10% = \frac{10}{100}

No. of left-handed students = \frac{10}{100} × 1,200

                                              = 120

8 0
3 years ago
Read 2 more answers
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
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