<u>Answer</u>:- No.
<u>Explanation</u> :-
<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>
<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.
<u>Here</u>,
hypotenuse = 12 (as it is the longest side)
and other two sides are 6 and 9.
----> 6^2 + 9^2 = 12^2
----> 36 + 81 = 144
----> 117 = 144
Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.
Answer:
f(x) = x^3 - x^2 -2x
Step-by-step explanation:
If x = a is a zero of a polynomial, then x-a is a factor of the polynomial. Given the factors of a polynomial, the polynomial can be obtained by multiplying the factors.
The factors of the given polynomial are;
x - 2
x + 1
x
Multiplying the first two factors;
(x-2)(x+1) = x^2 + x -2x -2
= x^2 -x -2
We finally multiply this result by x to obtain our polynomial;
f(x) = x ( x^2 -x -2)
= x^3 - x^2 -2x
which is a cubic polynomial since it has 3 roots.
2.48 > 2.471 > 2.463
5.723 < 5.724 < 5.725
7.64 < 7.65 < 7.68
Answer:
it’s A it is not given the ST and DE are parallel
Step-by-step explanation:
