Answer:
Explanation:
We want to know the value of 
when 
From here, we can find the factors of the quadratic equation, we need two numbers that multiplied give -400 and added -30. Since they are factors of 400, we can choose -20x20 or -40x10. When adding -20 and 20 the result is zero, but the sum of -40 and 10 is -30. Then:
The solutions of the quadratic equation are
and 
:
Since is a positive integer:
Answer:
Accrual shows face amount as revenue
revenue = $25,000
(12,000) (7/36)= $2,333 (regognized in 2017)
Total income reported in 2017 = $27,333
The next year she would show the remainder of 12,000 from 26 month contract
For tax purposes, max of 2 year deferral for payment recieved in advance.
Answer:
All of them.
Explanation:
Accounting systems are designed to show the increases and decreases in each financial statement item as a separate record. This record is called an account. In the T account, the debit is on the left and the credit is on the right.
The equity for credits and debits for each transaction is build into the accounting equation: assets = liabilities + equity. Because of this doble equality, this system is called double entry accounting system.
In balance sheet accounts:
-asset accounts debit for increases and credit for decreases.
-liability accounts debit for decreases and credit for increases.
-equity accounts debit for decreases and credit for increases.
Answer: (C) Revenue recognition principle
Explanation:
The revenue recognition is one of the type of principle that help[s in understanding the various types of accounts based guidelines that helps in identifying the particular condition in which the revenue is basically recognize.
The importance of third principle is that it helps in ensure the actual loss or the profit Margin that maintains the financial credibility.
According to the given question, the revenue recognition principle basically accepting the various types of accounting principle that helps in satisfying the performance obligations.
Therefore, Option (C) is correct answer.
Answer:
for (i = 0; datasamples[i] < NUM_POINTS ; ++i) {
if(datasamples[i] < minVal) {
datasamples[i] = datasamples[i] * 2;
}
}
Explanation:
In this particular problem, we are trying to look at each value in the datasamples array, and double it. This calls for the use of an index variable.
The index variable will keep track of the position within the array as we move from left to right. Starting on the left, at index 0, we will move right until we are at the end of the array.
++i takes care of incrementing the index variable each time the loop runs. This is what moves through the array.
The termination condition checks whether if we have iterates all values in the array. Once you've gone past all the values in the array the index variable is pointing all the way at the end.
As soon as the termination condition is false the loop will stop executing. So we will want to run your code while i (the index variable) is less than the size of the array (datasamples.length).
Once you've figured out the for loop bounds, simply check your conditional with an if-then statement before updating the values:
