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3 years ago

What are the numbers from least to greatest based on the -7 ,4, -2, 3

Mathematics

2 answers:

Anastaziya [24]3 years ago

8 0

Answer:

It would be -7,-2,3,4.

goldfiish [28.3K]3 years ago

5 0

Answer:

-7, -2, 3, 4

Step-by-step explanation:

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IRINA_888 [86]

What is your question that you want an answer to?

7 0

3 years ago

Factor the following: 2x2+9x+9

ryzh [129]

Answer: (2x+3)(x+3)

Step-by-step explanation:

Looking at this, you know that it must look something like

(? +3)(?+3) , because they must multiply to 9. The ?s must multiply to 2x^2, the most plausible values being 2x and x, ending us up with (2x+3)(x+3)

8 0

3 years ago

Read 2 more answers

Write an equation in standard form of the parabola that has the same shape as the graph of f(x)=5x^2or g(x)=-5x^2, but with a gi

pickupchik [31]

F(x)=5x^2 Has minimum (0,0)

g(x) = f(x) + 2 Shifts the graph two units up, then the minimum is 2+0=2.

h(x) = g(x+4) Shifts the graph four units left, then the minimum is at 0-4 = -4.

Then h(x) = 5(x+4)^2 + 2 has the minimum (-4,2)

And p(x) = -5(x+4)^2 + 2 has the maximum (-4,2)

4 0

4 years ago

I'll give points and brainalist for answer / explanation

Valentin [98]

Answer:

D. 8

Step-by-step explanation:

C= 2πr

π= 3.14

C= 25.12

25.12 = 2 * 3.14 * r

r= 4

d= 2r

d= 8

5 0

3 years ago

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

1 year ago