Answer:
um i can't really understand what your trying to do here
Step-by-step explanation:
<h3>
Answer: 74</h3>
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Work Shown:
h(x) = 7x-5
h(2) = 7(2)-5
h(2) = 14-5
h(2) = 9
f(h(2)) = f(9)
f(x) = x^2-7
f(9) = 9^2-7
f(9) = 81-7
f(9) = 74
f(h(2)) = 74
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Here's a slightly alternative approach:
f(x) = x^2 - 7
f(h(x)) = ( h(x) )^2 - 7
f(h(x)) = ( 7x-5 )^2 - 7
f(h(2)) = ( 7*2-5 )^2 - 7
f(h(2)) = ( 14-5 )^2 - 7
f(h(2)) = ( 9 )^2 - 7
f(h(2)) = 81 - 7
f(h(2)) = 74
9514 1404 393
Answer:
6, 9, 12, 15
Step-by-step explanation:
Comparing the given formula to the formula for the general term of an arithmetic sequence, ...
an = a1 +d(n -1)
we see that a1 = 6 and d = 3. That is, the first term of the sequence is 6 and each term is 3 more than the last.
The first 4 terms are 6, 9, 12, 15.
Answer:
20/500=25/625, the answer is d
Step-by-step explanation:
Since the numerator (how many failed) and the demoninator is how many wagons there were this would be the proper way to answer this question.
For this case we have the following function:
f = 1 / (2π√LC)
Clearing L we have:
√LC = 1 / (2πf)
LC = (1 / (2πf)) ^ 2
L = (1 / C) * (1 / (2πf)) ^ 2
Substituting values:
L = (1 / 0.0001) * (1 / (2 * 3.14 * 6.2)) ^ 2
L = 6.596253438
Round to the nearest tenth:
L = 6.6
Answer:
L = 6.6
