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Anon25 [30]
3 years ago
11

Please check my answers. Images below for both

Mathematics
2 answers:
Oksana_A [137]3 years ago
6 0
#4 should be the third choice.
#1 is -0.36 .
Zarrin [17]3 years ago
3 0
4. It can be helpful to consider the identities related to each of the answer choices.
• cot(θ) = 1/tan(θ) . . . . 1/tan(θ) + tan(θ) ≢ 1

• sec(θ) = 1/cos(θ), csc(θ)=1/sin(θ) . . . . 1/cos(θ)² + 1/sin(θ)² =
    (sin(θ)²+cos(θ)²)/(sin(θ)²cos(θ)²) = 1/(sin(θ)²cos(θ)²) ≢ 1

• sec(θ) = 1/cos(θ), tan(θ) = sin(θ)/cos(θ) . . . . (sin(θ)/cos(θ))² ≡ sin(θ)²×1/cos(θ)²
  tan(θ)² = sin(θ)²×sec(θ)² is the correct choice

• sec(θ) = 1/cos(θ), tan(θ) = sin(θ)/cos(θ) . . . . cos(θ)² ≠ 1/cos(θ)²×(sin(θ)/cos(θ))²


1. cot(290°) = -tan(20°) ≈ -0.36
  The second selection is a better choice.
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vladimir2022 [97]

<u>Given</u>:

The given function is f(x)=4x^2+2x+6

We need to determine the value of the discriminant f and also to determine the distinct real number zeros of f.

<u>Discriminant</u>:

The discriminant can be determined using the formula,

\Delta = b^2-4ac

Now, we shall determine the discriminant of the function f(x)=4x^2+2x+6

Substituting the values in the formula, we have;

\Delta=(2)^2-4(4)(6)

\Delta=4-96

\Delta=-92

Thus, the value of the discriminant of f is -92.

<u>Distinct roots:</u>

The distinct zeros of the function f can be determined by

(1) If \Delta>0, then the function has 2 real roots.

(2) If \Delta=0, then the function has 2 real roots ( or one repeated root).

(3) If \Delta, then the function has 2 imaginary roots (or no real roots).

Since, the discriminant is \Delta=-92 \ < \ 0 , then the function has no real roots  or 2 imaginary roots.

Thus, the function has 2 imaginary roots.

4 0
4 years ago
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Answer:

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Step-by-step explanation:

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However, this isn't proper notation for an arithmetic or geometric sequence.

8 0
4 years ago
Read 2 more answers
X/3 = 5/x-1 cross multiply
defon
15/2x-1
................
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