I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
Sum of n terms = a1 (r^n-1/ (r-1)
Sum of first one = 3 * (4^5 - 1) / 3 = 1023
.. 2nd = 5 * (6^2 - 1) / 5 = 35
.. 3rd = 5 ^4 - 1 / 4 = 156
.. 4th = 4 * (5^4 - 1) / 4 = 624
So in increasing order its 2nd, 3rd, 4th and first.
<span>i guess it means that its a cake with a top shaped like a hexagon. if you were to use paper and cut out a hexagon then fold it, you would find out that it has 9 diagonals(meaning that you are able to fold it equally into 9 pieces). when it is unfolded, you will see 24 pieces and you will have to figure out which of the 24 pieces are triangles and which are not. after that, you calculate the percentage of triangles.
after you are finished with the paper, you apply the information to the cake.
i'm not sure if this is right, but you can try it out.</span>
Answer:
x=7
Step-by-step explanation:
This is a vertical line. Vertical lines are of the form x=
The x coordinate is 7
x=7
Answer:
simply use photomath its an app