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aleksandrvk [35]
3 years ago
14

A rectangular garden is 8 feet long and 4 feet wide. A second rectangular garden has dimensions that are 54 the dimensions of th

e first garden. What is the percent of change in perimeter from the first garden to the second garden?ftyrt
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0
We have the perimeter of first dimension 2(8 + 4) = 24;
The perimeter of the second dimension is 2( 8 + 54 + 4 + 54 ) = 240
We calculate p/100 = 24/240;
Then p/100 = 1/10;
p = 100/10;
p = 10;
Finally, 10% is the answer.
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A score of 314 is needed to be in the top 25% of students who take this exam.

Step-by-step explanation:

We are given that one of the tests provided by the NAEP assesses the reading skills of twelfth-grade students. In recent years, the national mean score was 289 and the standard deviation was 37.

Let X = <u><em>scores of the tests provided by the NAEP</em></u>

The z-score probability distribution for the normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = national mean score = 289

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Now, we have to find how high a score is needed to be in the top 25% of students who take this exam, that means;

            P(X > x) = 0.25     {where x is the required score}

            P( \frac{X-\mu}{\sigma} > \frac{x-289}{37} ) = 0.25

            P(Z > \frac{x-289}{37} ) = 0.25

In the z table, the critial value of z that represents the top 25% of the area is given as 0.6745, that is;

                        \frac{x-289}{37}=0.6745

                        {x-289}=0.6745\times 37

                        x = 289 + 24.96 = 313.96 ≈ 314

Hence, a score of 314 is needed to be in the top 25% of students who take this exam.

7 0
3 years ago
What is the length of the hypotenuse for a right triangle with legs of length 9 and 40? A) 41 B) 43 C) 45 D) 47
Katena32 [7]

Answer:

A) 41

Step-by-step explanation:

Let the hypotenuse be denoted by h

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According to the Pythagoras theorem

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h =  \sqrt{1600 + 81}  =  \sqrt{1681}

h = 41

8 0
3 years ago
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