0.2 = 2/10 = 1/5 but 0.02 = 2/100 = 1/50 so 1/5 > 1/50 :D
Answer:
z = 2.1784 > 1.96,
Reject the null hypothesis
Step-by-step explanation:
For the males:
n1 = 162, x1 = 63
P1 = x 1/ n1 = 0.3889
For the Females:
n2 = 333,
x2 = 97
P 2 = x2/n2
= 0.2913
P 1= P2 Null hypothesis
P 1 is not equal to P 2 alternative hypothesis
Pooled proportion:
P= (x1 + x2) /( n1+ n2)
= (63 + 97) / (162 + 333)= 0.3232
Test statistics :
Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)
0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)
=2.1784
c) Critical value :
Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960
Reject H o if z < -1.96 or if z > 1.96
d) Decision:
z = 2.1784 > 1.96,
Reject the null hypothesis
Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy =
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) = 
- 
⇒ x + iy = 
⇒ x + iy = 
[ ∵ 
]
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
The number which appears most often in a set of numbers. Example: in {6, 3, 3, 6, 3, 5, 9, 3} the Mode<span> is 3 (it occurs most often). Does this help???</span>
