Answer:
10 ways
Step-by-step explanation:
The number of ways in which five basketball players could be placed in three positions is:
5
= ![\frac{5!}{(5-3)!3!}](https://tex.z-dn.net/?f=%5Cfrac%7B5%21%7D%7B%285-3%29%213%21%7D)
= ![\frac{5!}{3!2!}](https://tex.z-dn.net/?f=%5Cfrac%7B5%21%7D%7B3%212%21%7D)
= ![\frac{5*4*3*2!}{3*2*2!}](https://tex.z-dn.net/?f=%5Cfrac%7B5%2A4%2A3%2A2%21%7D%7B3%2A2%2A2%21%7D)
= 5 × 2
= 10
The basketball players can be arranged in 10 ways.
Answer:
y = -2x + 3
Step-by-step explanation:
Let's just put the three points together.
(-1, 5) (-4, 11) (-7, 17)
First, let's find the slope with y2 - y1/x2 - x1
Plug in using (-1, 5) and (-4, 11)
11 - 5/-4 + 1 = 6/-3 (simplify)
-2 is the slope
Now plug in (-7, 17) in the equation to get b or the y-intercept)
y = mx + b
17 = -2(-7) + b
17 = 14 + b (subtract 14 on both sides)
3 = b
y = -2x + 3
Distribute the signs: 12-14+9x
so, -2+9x
The total space needed is 600 feet. Because 5 tables times 72 feet is 360 and 5 tables times 48 feet a part is 249. You add them and it comes out to be 600. It should be worked out like this 5(72+48)
Answer:
120 blocks total
Step-by-step explanation:
All of the little cubes have side length 2" Thus, the 11" height of the box cannot be used entirely: we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.
Start at the bottom of the box. The dimensions of the bottom are 12" by 8". Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide. We can add 3 more such rows to fill the available 8" width of the box bottom. That's 6*4, or 24 blocks.
We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.
5 layers times 24 blocks per layer comes to 120 blocks total.