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Radda [10]
3 years ago
7

The caffeine content of a cup of home-brewed coffee is a normally distributed random variable with a mean of 115 mg and a standa

rd deviation of 20 mg. What is the 50th percentile value of caffeine content in a cup of home-brewed coffee
Mathematics
1 answer:
sdas [7]3 years ago
3 0

Answer:

115 mg

Step-by-step explanation:

The 50th percentile has a corresponding z-score of z = 0. The z-score, for any given value of caffeine, X, is given by:

z = \frac{X-mean}{SD}

Therefore, if z=0, then X must be equal to the mean value of the normal distribution, which is 115 mg. Thus, the 50th percentile value of caffeine content is 115 mg.

You might be interested in
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
SOMEONE PLEASE HELP<br> find the greatest common factor <br> 14g5h2, 56g3h4, 77g3h2
andrezito [222]

Answer:

\large\boxed{GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=g^3h^2}

Step-by-step explanation:

14g^5h^2=2\cdot7\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot g\cdot g\cdot \boxed{h}\cdot \boxed{h}\\\\56g^3h^4=2\cdot2\cdot2\cdot7\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\cdot h\cdot h\\\\77g^3h^2=7\cdot11\cdot\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}\\\\GCF(14g^5h^2,\ 56g^3h^4,\ 77g^3h^2)=\boxed{g}\cdot \boxed{g}\cdot \boxed{g}\cdot \boxed{h}\cdot \boxed{h}=g^3h^2

8 0
3 years ago
-12b +6b -4b was the answer yo
Helen [10]

- 10b

when we add -12 and 6 we get -6

after that we subtract -6 from -4 to get -10

3 0
3 years ago
Read 2 more answers
Only answer if you're very good at math.Please I keep on posting this but nobody is helping me.
hichkok12 [17]
I believe A. but Major guess tho
3 0
3 years ago
How many times does 45 go into 60
mart [117]
45 would be able to go into 60 only 1 time, with a remainder of 15.

1 r^15
5 0
3 years ago
Read 2 more answers
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