The caffeine content of a cup of home-brewed coffee is a normally distributed random variable with a mean of 115 mg and a standa
1 answer:
Answer:
115 mg
Step-by-step explanation:
The 50th percentile has a corresponding z-score of z = 0. The z-score, for any given value of caffeine, X, is given by:
Therefore, if z=0, then X must be equal to the mean value of the normal distribution, which is 115 mg. Thus, the 50th percentile value of caffeine content is 115 mg.
You might be interested in