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allochka39001 [22]
3 years ago
15

A concert organizer recorded the number of people in different age groups who attended a concert. She then created the following

histogram:
Histogram with title Concert Attendance, horizontal axis labeled Age Group (year) with bins 0 to 19, 20 to 39, 40 to 59, and 60 to 79 and vertical axis labeled Number of People with values from 0 to 60 at intervals of 10. The first bin goes to 40, the second goes to 50, the third goes to 30, and the last goes to 20.

Which of the following statements best compares the height of the bars of the histogram?

There are more participants in the 0–19 age group than in the 40–59 and 60–79 groups combined.
There are more participants in the 20–39 age group than in the 40–59 and 60–79 groups combined.
There are twice as many participants in the 0–19 age group than in the 60–79 age group.
There are 3 times as many participants in the 60–79 age group than in the 20–39 age group.
Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0
This is the concept of statistics. The correct answer is:
There are twice as many participants in the 0-19 age group than in the 60-79 age group. This is because:
Number of participants in the age group 0-19 is 40 participants
Number of participants in the age group 60-79 is 20 participants.
From the above we see that the age group 0-19 is double the number of age group 60-79 years old. 
Therefore our answer is option C
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S=(1 r)<br> c. find c if s = r 174 and r= 45%
stepladder [879]
The question is incorrect because of the apparent contradiction the question makes.
First statement says that a quantity S is equal to quantity r.
The second statement says that S = 174r. 
Moreover, the quantity C is not correctly linked with the equation. Please either correct the question or explain the ambiguity.
4 0
3 years ago
What is the midpoint of the segment shown below?
Aneli [31]

Answer:

(1, -3/2)

Step-by-step explanation:

The x coordinate is the same for both endpoints so the x coordinate for the midpoint is 1

The y coordinate for the midpoint is found by adding the two y coordinates and dividing by 2

(2+-5)/2 = -3/2

The midpoint is

(1, -3/2)

5 0
3 years ago
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In right angle RST of cos R what is the length of RT A. 7.2 ft. B. 20 ft. C. 24 ft. D. 72 ft
andrey2020 [161]

Answer:

b

Step-by-step explanation:

it can be 20 ft that is what l think

6 0
3 years ago
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
3 years ago
She worked a total of 15 hours. If she makes $15 per hour tutoring and $9 per hour at the grocery store and made a total of $159
Ugo [173]

Answer:

11 hours she worked at the grocery store

Step-by-step explanation:

assuming,

the number of hours worked at tutoring = x

the number of hours worked at grocery store = y

which means,

the amount she made at tutoring = x* $15

the amount she made at grocery store = y*$9

we have 2 equations

<em>total number of hours</em>

1) x+y= 15  

<em>total amount she earned</em>

2) x* $15+ y* $9= $159

From equation 1

x+y= 15  

x=15-y

<em>we replace this x value in equation 2</em>

x* $15+ y* $9= $159

(15-y)* $15+ y* $9= $159

(15*15)- 15y+9y=159

225-6y=159

225-159=6y

66=6y

66/6=y

<u>11=y</u>  <em>the number of hours she worked at grocery store. </em>

<em>we place y=11 in our derived x equation</em>

x=15-y

x=15-11

<u><em>x=4 </em></u><em>the number of hours she worked at tutoring. </em>

3 0
3 years ago
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