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melomori [17]
3 years ago
6

Please answer fast, I need great answers!!!!! This is mathematics.

Mathematics
1 answer:
Fantom [35]3 years ago
7 0
20, 25, 30, 30, 31, 40, 41, 49
median = 30.5

lower IQR = 27.5
upper IQR = 40.5

Range IQR = 40.5 - 27.5 = 13

answer is 13
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Is this a fair or biased sample.
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2 years ago
Simplify: -3(4x - 5)
nata0808 [166]

Answer:

8x - 26 \\ -16x - 4 \\ -12x + 15

Step-by-step explanation:

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For the third and first exercises, you just use the Distributive Property, and for the second exercise, all you are doing is combining like-terms.

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3 years ago
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lozanna [386]

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="
beks73 [17]

The result of expanding the trigonometry expression \sin^2(\theta) * (1 + \cos(\theta)) is cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

<h3>How to evaluate the expression?</h3>

The expression is given as:

\sin^2(\theta) * (1 + \cos(\theta))

Express \sin^2(\theta) as 1 - \cos^2(\theta).

So, we have:

\sin^2(\theta) * (1 + \cos(\theta)) =  (1- \cos^2(\theta)) * (1 + \cos(\theta))

Open the bracket

\sin^2(\theta) * (1 + \cos(\theta)) =  1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Express 1 as cos°(Ф)

\sin^2(\theta) * (1 + \cos(\theta)) =  cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Hence, the result of expanding the trigonometry expression \sin^2(\theta) * (1 + \cos(\theta)) is cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

3 0
2 years ago
What is the lenght in miles of the field
maw [93]
(Perimeter/6)2= Length
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4 years ago
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