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andre [41]
3 years ago
7

Easy POINTS Awnser These

Mathematics
2 answers:
labwork [276]3 years ago
7 0
Cant really see it like that
Romashka [77]3 years ago
3 0

Answer:

i cant read it

Step-by-step explanation:

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Find the measure of K
eimsori [14]

Answer:

50+50=100

180-100=50

The answer is 40

5 0
3 years ago
Alison bought one t-shirt for $10.20 and another for $18.90 what is the total amount she spent?
Rus_ich [418]

10.20 + 18.90 = $29.10

6 0
3 years ago
Is it true that the planes x + 2y − 2z = 7 and x + 2y − 2z = −5 are two units away from the plane x + 2y − 2z = 1?
zhuklara [117]

Lets Find It Out..

First we'll find the equation of ALL planes parallel to the original one.

As a model consider this lesson:

Equation of a plane parallel to other

The normal vector is:
<span><span>→n</span>=<1,2−2></span>

The equation of the plane parallel to the original one passing through <span>P<span>(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span></span>is:

<span><span>→n</span>⋅< x−<span>x0</span>,y−<span>y0</span>,z−<span>z0</span>>=0</span>
<span><1,2,−2>⋅<x−<span>x0</span>,y−<span>y0</span>,z−<span>z0</span>>=0</span>
<span>x−<span>x0</span>+2y−2<span>y0</span>−2z+2<span>z0</span>=0</span>
<span>x+2y−2z−<span>x0</span>−2<span>y0</span>+2<span>z0</span>=0</span>

Or

<span>x+2y−2z+d=0</span> [1]
where <span>a=1</span>, <span>b=2</span>, <span>c=−2</span> and <span>d=−<span>x0</span>−2<span>y0</span>+2<span>z0</span></span>

Now we'll find planes that obey the previous formula and at a distance of 2 units from a point in the original plane. (We should expect 2 results, one for each half-space delimited by the original plane.)
As a model consider this lesson:

Distance between 2 parallel planes

In the original plane let's choose a point.
For instance, when <span>x=0</span> and <span>y=0</span>:
<span>x+2y−2z=1</span> => <span>0+2⋅0−2z=1</span> => <span>z=−<span>12</span></span>
<span>→<span>P1</span><span>(0,0,−<span>12</span>)</span></span>

In the formula of the distance between a point and a plane (not any plane but a plane parallel to the original one, equation [1] ), keeping <span>D=2</span>, and d as d itself, we get:

<span><span>D=<span><span>|a<span>x1</span>+b<span>y1</span>+c<span>z1</span>+d|</span><span>√<span><span>a2</span>+<span>b2</span>+<span>c2</span></span></span></span></span>
<span>2=<span><span><span>∣∣</span>1⋅0+2⋅0+<span>(−2)</span>⋅<span>(−<span>12</span>)</span>+d<span>∣∣</span></span><span>√<span>1+4+4</span></span></span></span>
<span><span>|d+1|</span>=2⋅3</span> => <span><span>|d+1|</span>=6</span>First solution:
<span>d+1=6</span> => <span>d=5</span>
<span>→x+2y−2z+5=0</span>Second solution:
<span>d+1=−6</span> => <span>d=−7</span>
<span>→x+2y−2z−7=<span>0</span></span></span>
8 0
3 years ago
Beginning at 8:30 A.M., tours of the national capitol and the White House begin at a tour agency. Tours for the national capital
Rashid [163]

When do the tours stop?

3 0
3 years ago
Read 2 more answers
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

3 0
3 years ago
Read 2 more answers
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