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Inessa [10]
3 years ago
7

PLEASE HELPPPP WITH THIS

Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0

Answer:The distance formula itself is actually derived from the Pythagorean Theorem which is a 2 + b 2 = c 2 {a^2} + {b^2} = {c^2} a2+b2=c2

Step-by-step explanation:

tekilochka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

slope = y2-y1/x2-x1

1 -3 . 3 1

(1 - (-3))/(3-1)

4/2

2

Slope = 2

y = mx + b

y = 2x -5

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Solve for x ………………………..
Anna71 [15]

Answer:

44 degrees

Step-by-step explanation:

Since the triangle is a SAS triangle,the two missing angles are congruent,so first subtract 92 from 180, which is 88, then divide that by 2 to get your answer.

8 0
3 years ago
Match each spherical volume to the largest cross sectional area of that sphere
zlopas [31]

Answer:

Part 1) 324\pi\ units^{2} ------> 7,776\pi\ units^{3}

Part 2) 36\pi\ units^{2} ------> 288\pi\ units^{3}

Part 3) 81\pi\ units^{2} ------> 972\pi\ units^{3}

Part 4) 144\pi\ units^{2} ------> 2,304\pi\ units^{3}

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

A=324\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

324\pi=\pi r^{2}

Solve for r

r^{2}=324

r=18\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=18\ units

substitute

V=\frac{4}{3}\pi (18)^{3}

V=7,776\pi\ units^{3}

Part 2) we have

A=36\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

36\pi=\pi r^{2}

Solve for r

r^{2}=36

r=6\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=6\ units

substitute

V=\frac{4}{3}\pi (6)^{3}

V=288\pi\ units^{3}

Part 3) we have

A=81\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

81\pi=\pi r^{2}

Solve for r

r^{2}=81

r=9\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=9\ units

substitute

V=\frac{4}{3}\pi (9)^{3}

V=972\pi\ units^{3}

Part 4) we have

A=144\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

144\pi=\pi r^{2}

Solve for r

r^{2}=144

r=12\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=12\ units

substitute

V=\frac{4}{3}\pi (12)^{3}

V=2,304\pi\ units^{3}

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3 years ago
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