Please help!!!! Thank you!!!! (25 points)

larisa [96]

Answer
0.47qt a sec
Reason
Convert the gallons to quart using the formula “q=4g”
q=4(7)= 28
So we learn that it’s 28 quarts a minute. To figure it out by the second divide by 60.
28 divided by 60 equals 0.4667
Round to the nearest hundredth and it equals
0.47
There for it is 0.47 quarts a second.

6 0

3 years ago

What is the correct answer

frozen [14]

43 g per eggs
4 eggs weight are 172 g
so 1 egg weight is 172/4
= 43

7 0

3 years ago

Read 2 more answers

Which statement is correct PLEASE HELP ILL GOVE YOU BRAINLIEST.

Valentin [98]

The first one is correct, just match the numbers with the corresponding sides of each triangle

6 0

3 years ago

Eddie's Evergreens sells Christmas trees and wreaths. Trees cost 3 dollars more than 4 times the price of each wreath. It costs

kari74 [83]

Answer:

$W = 16$

$T = 67$

Step-by-step explanation:

Represent trees with T and wreaths with W

Given

$T = 3 + 4 * W$

$2 * W + T = 99$

Solving (a): Cost of W

Substitute 3 + 4 * W for T in the second equation

$2*W + 3 + 4 * W = 99$

$2W + 3 + 4 W = 99$

Collect Like Terms

$2W + 4 W = 99 - 3$

$6W = 96$

Divide through by 6

$W =\frac{96}{6}$

$W = 16$

Hence, each wreath costs $16

Solving (b): Cost of T

$T = 3 + 4 * W$

Substitute 16 for W

$T = 3 + 4 * 16$

$T = 3 + 64$

$T = 67$

Hence, each tree costs $67

3 0

2 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

$178=x^2+3x-y\\ \\ -6=4x-3y$

8 0

3 years ago

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