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2 years ago

Can someone please help me??

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

3 0

Answer:

The maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

Step-by-step explanation:

Given;

F = 4y - 3x

The function is subject to y ≤ 2x - 1,

y ≥ -2x + 3,

x ≤ 3

y ≤ 2x - 1

- ( y ≥ -2x + 3)

-------------------

0 ≤ 4x - 4

4 ≤ 4x

1 ≤ x

thus, 1 ≤ x ≤ 3

When x = 3

y ≤ 2x - 1 ⇒ y ≤ 2(3) - 1, ⇒ y ≤ 5

y ≥ -2x + 3, ⇒ y ≥ -2(3) + 3, ⇒ y ≥ - 3

thus, -3 ≤ y ≤ 5

When x = 1

y ≤ 2x - 1 ⇒ y ≤ 2(1) - 1, ⇒ y ≤ 1

y ≥ -2x + 3, ⇒ y ≥ -2(1) + 3, ⇒ y ≥ 1

when x = 1 and y = 1

F = 4(1) - 3(1)

F = 1

when y = -3, and x = 3

F = 4(-3) - 3(3)

F = -12 - 9

F = - 21

When y = 5 and x = 3

F = 4(5) - 3(3)

F = 20 - 9

F = 11

Therefore, the maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

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Answer:

The slope is 2 and the y-intercept is -6

Step-by-step explanation:

we know that

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$y=mx+b$

where

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b is the y-intercept or initial value (value of y when the value of x is equal to zero)

In this problem we have

$y=2x-6$

therefore

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$m=2$

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$b=-6$

<u><em>Verify</em></u>

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$y=2(0)-6=-6$ ---> is ok

8 0

3 years ago

Which of the following expressions represents "twelve diminished by six times a number"?

ahrayia [7]

Diminished means "made smaller", so in other words, subtracted. This makes the phrase "twelve subtracted by six times a number", or more simply "twelve minus six times a number".

Answer:
A. 12 - 6n

4 0

3 years ago

Read 2 more answers

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

What is a35 for the arithmetic sequence presented in the table below?

Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

7 0

3 years ago

Which of the following is the mid point of the line segment with endpoints -3 and 2 (a)5/2 (b) 1 (c) -1/2 (d) -1 (e)-5/2

scoray [572]

Answer:

2,5 b 1 c 0,5 d -1 e 2,5

Step-by-step explanation:

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3 years ago