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Mademuasel [1]
4 years ago
6

Solve for x 2x^2/3=dg

Mathematics
1 answer:
natta225 [31]4 years ago
3 0
(2x²/3)=dg

2x²=3dg

x²=((3dg)/2)

So x=√((3dg)/2) or x=-√((3dg)/2)
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