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Mademuasel [1]
4 years ago
6

Solve for x 2x^2/3=dg

Mathematics
1 answer:
natta225 [31]4 years ago
3 0
(2x²/3)=dg

2x²=3dg

x²=((3dg)/2)

So x=√((3dg)/2) or x=-√((3dg)/2)
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Santiago receives an allowance of $7 every week . How much total does he receive in 4 week?
goblinko [34]
7 weeks x 4
7 x 4 = 28
He received 28$
3 0
3 years ago
Read 2 more answers
Please show steps to solve y=3\2x-2 y=x+2
castortr0y [4]
Substitute what you know y is equal to into the equation:
y = x + 2
3/2x - 2 = x + 2

Then you can simplify your equation by multiplying both sides by 2 to eliminate the fraction which will give you:

3x - 4 = 2x + 4

Add the -4 to the other side to get 8 and subtract the 2x from the 3x so you have:

x = 8    Now solve for y by substituting your value for x into the other equation:
y = 3/2(8) - 2    Simplify by combining your numbers and you get:
y = 10     Check your answer by substituting y and x into the original equation:
(10) = (8) - 2
Correctly done! So your answers are x = 8 and y = 10
6 0
4 years ago
The value of x must be greater than<br> B<br> 12<br> 0<br> O 1<br> А<br> 15<br> O 3<br> O 7
IrinaK [193]

Answer:

x > 3

Step-by-step explanation:

Given 2 sides of a triangle then the third side x will be

difference of sides < x < sum of sides , that is

15 - 12 < x < 15 + 12, so

3 < x < 27

Thus x > 3

8 0
3 years ago
X<br> 8<br> 17<br> Find the exact value of x.<br> X=
Furkat [3]

Answer:

621

629

Step-by-step explanation:

We know that

sin

(

x

+

y

)

=

sin

x

cos

y

+

sin

y

cos

x

If

cos

x

=

8

17

and

sin

y

=

12

37

We can use,

cos

2

x

+

sin

2

x

=

1

and

cos

2

y

+

sin

2

y

=

1

To calculate

sin

x

and

cos

y

sin

2

x

=

1

−

cos

2

x

=

1

−

(

8

17

)

2

=

225

17

2

sin

x

=

15

17

cos

2

y

=

1

−

sin

2

y

=

1

−

(

12

37

)

2

=

1225

37

2

cos

y

=

35

37

so,

sin

(

x

+

y

)

=

15

17

⋅

35

37

+

12

37

⋅

8

17

=

621

629

Answer link

Shwetank Mauria

Nov 22, 2016

sin

(

x

+

y

)

=

621

629

or

−

429

629

depending on the quadrant in which sine and cosine lie.

Explanation:

Before we commence further, it may be mentioned that as

cos

x

=

8

17

,

x

is in

Q

1

or

Q

4

i.e.

sin

x

could be positive or negative and as

sin

y

=

12

37

,

y

is in

Q

1

or

Q

2

i.e.

cos

y

could be positive or negative.

Hence four combinations for

(

x

+

y

)

are there and for

sin

(

x

+

y

)

=

sin

x

cos

y

+

cos

x

sin

y

, there are four possibilities.

Now as

cos

x

=

8

17

,

sin

x

=

√

1

−

(

8

17

)

2

=

√

1

−

64

289

=

√

225

289

=

±

15

17

and

as

sin

y

=

12

37

,

cos

y

=

√

1

−

(

12

37

)

2

=

√

1

−

144

1369

=

√

1225

1369

=

±

35

37

Hence,

(1) when

x

and

y

are in

Q

1

sin

(

x

+

y

)

=

15

17

×

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(2) when

x

is in

Q

1

and

y

is in

Q

2

sin

(

x

+

y

)

=

15

17

×

−

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

(3) when

x

is in

Q

4

and

y

is in

Q

2

sin

(

x

+

y

)

=

−

15

17

×

−

35

37

+

8

17

×

12

37

=

525

+

96

629

=

621

629

(4) when

x

is in

Q

4

and

y

is in

Q

1

sin

(

x

+

y

)

=

−

15

17

×

35

37

+

8

17

×

12

37

=

−

525

+

96

629

=

−

429

629

Hence,

sin

(

x

+

y

)

=

621

629

or

−

429

629

7 0
3 years ago
Helps me pleaseeeee ;)
Dmitry_Shevchenko [17]
By 8
40
48
Hope this helps *smiles*
Sorry if it’s wrong
8 0
3 years ago
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