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3 years ago

What is the distance between −93 and 114 on a number line?

Mathematics

2 answers:

natali 33 [55]3 years ago

7 0

Answer:

207.

Step-by-step explanation:

Whitepunk [10]3 years ago

4 0

Answer:

207 numbers away from each other

Step-by-step explanation:

to get from 0 to 114 that is 114 numbers

then to get from -93 to 0 which is 93 numbers

add 114 and 93 to get 207

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

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3 years ago

Is my answer right to this problem

VLD [36.1K]

Yes it’s right for this problem

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2 years ago

Wastewater is filling barrels at the rate of 11 quarts per hour. The recycling facility picks up 120 full barrels on each trip,

givi [52]

120 barrels x 12 quarts per barrel = 1440 total quarts

1440 quarts / 11 quarts per hour = 130.91 hours to fill all the barrels

1 day = 24 hours

130.91 hours / 24 hours = 5.45 days = 5.5 days

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3 years ago

an airplane is cruising at an altitude of 40000 feet begins at a distant to land it loses altitude at a rate of 1500 feet per mi

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27.7-. or is it something else?!?!?

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3 years ago

Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than

liraira [26]

Given:

Atul has $\dfrac{2}{3}$ lb of candy.

Jose has $\dfrac{3}{5}$ lb of candy.

Maria has $\dfrac{1}{2}$ lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has $\dfrac{1}{2}$ lb less than Jose, therefore

Maria has = $\dfrac{3}{5}-\dfrac{1}{2}$ lb

Maria has = $\dfrac{6-5}{10}$ lb

Maria has = $\dfrac{1}{10}$ lb

Difference between the candies Atul and Maria have.

Difference = $\dfrac{2}{3}-\dfrac{1}{10}$ lb

Difference = $\dfrac{20-3}{30}$ lb

Difference = $\dfrac{17}{30}$ lb

Therefore, Atul have $\dfrac{17}{30}$ lb of candy more than Maria.

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3 years ago