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2 years ago

What is the slope of the line?

Mathematics

2 answers:

nexus9112 [7]2 years ago

7 0

Answer:

y = x + 5

1 would be the slope AKA m

Step-by-step explanation:

y = mx + b

mx is change of y to the change in x.

m is the slope

As you can see in the problem above, everytime y moves up 1, x moves to the right 1.

b is the y intercept - where is y when x is at 0?

This will help you find the slope of future problems hopefully. :)

Sergeu [11.5K]2 years ago

5 0

Answer:

Step-by-step explanation:

$\frac{rise}{run}=slope$

$\frac{1}{1} =1$

therefore the slope is 1

plz mark me brainliest. :)

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Solve ax-b/d=c, for x

Kitty [74]

Answer:

x = cd + b / a

Step-by-step explanation:

ax - b / d = c

ax - b = cd

ax = cd + b

x = cd + b / a

5 0

2 years ago

What is the equation of the line that is perpendicular to f(x) and passes through the point (4, –6)? a.4x + 3y = –2 b. 3x + 4y =

user100 [1]

Answer:

Step-by-step explanation: because its even

4 0

3 years ago

if the volume of a storage room is 24 cubic feet its length is 3 feet and its width is 2 feet what is the height

viva [34]

Answer:

Step-by-step explanation:

V = L*w*h

L = 3

w = 2

h = ?

V = 24

24 = 2*3 * h Combine the right

24 = 6* h Divide both sides by 6

24/6 = 6h/6

4 = h

6 0

1 year ago

Find the slope between these two points:<br><br><br><br> (4,2) and (10,5)

mart [117]

Answer:

Slope is 1/2

Step-by-step explanation:

Slope Formula = m = y2 - y1/x2 - x1

Point = (4,2) and (10,5)

m = y2 - y1/x2 - x1

m = 5 - 2/10 - 4

m = 3/6

m = 1/2

4 0

2 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete the st

Zina [86]

Question:

If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.

Answer:

$Sin\theta = \frac{-15}{17}$

$Tan\theta = \frac{15}{8}$

Step-by-step explanation:

Given

cos(θ) =-8/17

Required

sin(θ) = __

tan(θ) =__

The first step is to determine the length of the third side

Given that

$cos(\theta) = \frac{Adj}{Hyp}$

Where Adj and Hyp represent Adjacent and Hypotenuse

$cos(\theta) = \frac{-8}{17}$

By comparison

$Adj = -8\ and\ Hyp = 17$

Using Pythagoras

$Hyp^2 = Adj^2 + Opp^2$

By Substitution

$17^2 = (-8)^2 + Opp^2$

$289 = 64 + Opp^2$

Subtract 64 from both sides

$289 - 64 = 64 - 64 + Opp^2$

$225 = Opp^2$

Take square roots of both sides

$\sqrt{225} = \sqrt{Opp^2}$

$\sqrt{225} = Opp$

$15 = Opp$

$Opp = 15$

The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

$Opp = -15$

From trigonometry

$Sin\theta = \frac{Opp}{Hyp}$

$Sin\theta = \frac{-15}{17}$

Also from trigonometry

$Tan\theta = Sin\theta / Cos\theta$

$Tan\theta = \frac{-15}{17} / \frac{-8}{17}$

$Tan\theta = \frac{-15}{17} * \frac{-17}{8}$

$Tan\theta = \frac{-15 * -17}{17 * 8}$

$Tan\theta = \frac{15 * 17}{17 * 8}$

$Tan\theta = \frac{15}{8}$

5 0

2 years ago