Write a quadratic equation with -4 and 3/2 as it’s roots. Write the equation in the form ax^2 + bx + c = 0, where a, b, and c ar
1 answer:
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Answer:
2x² +5x -12 = 0
Step-by-step explanation:
When p and q are roots of a quadratic, its factored form can be written as ...
(x -p)(x -q) = 0
Here, the roots are given as -4 and 3/2, so the factored form would be ...
(x -(-4))(x -(3/2) = 0
Multiplying by 2 gives us ...
(x +4)(2x -3) = 0
Expanding the product, we find the desired quadratic is ...
2x² +5x -12 = 0
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Answer:
Your equation is
Step-by-step explanation:
Well, the center origin of the circle is given (h,k) = (1,-1).
We have to find our radius as they gave us a point. from origin to the edge of the circle.
Using the formula: (x - h)^2 + (y - k)^2 = r^2
Plug in our (h,k) = (1,-1) and (x,y) = (0.5,-1) to solve for radius.
(x - h)^2 + (y - k)^2 = r^2
(0.5 - (1))^2 + (-1 - (-1))^2 = r^2
(-0.5)^2 + (0)^2 = r^2
1/4= r^2
r^2 = 1/4
r = 1/2