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lozanna [386]
2 years ago
9

Write a quadratic equation with -4 and 3/2 as it’s roots. Write the equation in the form ax^2 + bx + c = 0, where a, b, and c ar

e integers.
Mathematics
1 answer:
jonny [76]2 years ago
5 0

9514 1404 393

Answer:

  2x² +5x -12 = 0

Step-by-step explanation:

When p and q are roots of a quadratic, its factored form can be written as ...

  (x -p)(x -q) = 0

Here, the roots are given as -4 and 3/2, so the factored form would be ...

  (x -(-4))(x -(3/2) = 0

Multiplying by 2 gives us ...

  (x +4)(2x -3) = 0

Expanding the product, we find the desired quadratic is ...

  2x² +5x -12 = 0

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The 12th term in a sequence with a common difference of-9 is -106. which of the following formulas can be used to represent this
Effectus [21]

Answer:

T12=a-99=106

Step-by-step explanation:

that's the answer

6 0
2 years ago
The lowest temperature in January was less than−6°. Which could be the lowest temperature in January?
PIT_PIT [208]

Answer

-30

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve the following system of equations for all three variables.
xz_007 [3.2K]

Answer:

Step-by-step explanation:

-2x + 3y – 4z = 8    ----------------(I)

5x – 3y + 5z = -8    -----------------(II)

7x – 3y + 3z = 8 ------------------(III)

Add equation (I) & (II) and thus y will be eliminated

(I)        -2x + 3y – 4z = 8

(II)        <u>5x – 3y + 5z = -8</u>    {Add}

           3x          + z  = 0   ------------------------(A)

Multiply equation (II) by (-1) and then add with equation (III). Thus y will be eliminated.

(II) * (-1)         -5x + 3y - 5z = +8

                     <u>7x – 3y + 3z = 8</u>   {Add}

                     2x         -2z   = 16   ---------------(B)

Multiply equation (A) by 2 and then add. Thus z will be eliminated and we will get the value of x

(A) * 2          6x + 2z = 0

(B)                 <u>2x - 2z  = 16</u>   {Add}

                     8x         = 16

Divide both sides by 8

                             x = 16/8

                          x = 2

Plugin x = 2 in equation (A)

3x + z = 0

3*2 + z = 0

 6 + z = 0

       z = -6

Plug in x = 2 and z  = - 6 in equation (I)

-2x +3y - 4z = 8

-2*2 + 3y - 4*(-6) = 8

-4 + 3y + 24 = 8

     3y   + 20 = 8

               3y = 8 - 20

               3y = -12

                 y = -12/3

y = -4

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7 0
3 years ago
Read 2 more answers
The ​half-life of a radioactive element is 130​ days, but your sample will not be useful to you after​ 80% of the radioactive nu
gtnhenbr [62]

Answer:

We can use the sample about 42 days.

Step-by-step explanation:

Decay Equation:

\frac{dN}{dt}\propto -N

\Rightarrow \frac{dN}{dt} =-\lambda N

\Rightarrow \frac{dN}{N} =-\lambda dt

Integrating both sides

\int \frac{dN}{N} =\int\lambda dt

\Rightarrow ln|N|=-\lambda t+c

When t=0, N=N_0 = initial amount

\Rightarrow ln|N_0|=-\lambda .0+c

\Rightarrow c= ln|N_0|

\therefore ln|N|=-\lambda t+ln|N_0|

\Rightarrow ln|N|-ln|N_0|=-\lambda t

\Rightarrow ln|\frac{N}{N_0}|=-\lambda t.......(1)

                            \frac{N}{N_0}=e^{-\lambda t}.........(2)

Logarithm:

  • ln|\frac mn|= ln|m|-ln|n|
  • ln|ab|=ln|a|+ln|b|
  • ln|e^a|=a
  • ln|a|=b \Rightarrow a=e^b
  • ln|1|=0

130 days is the half-life of the given radioactive element.

For half life,

N=\frac12 N_0,  t=t_\frac12=130 days.

we plug all values in equation (1)

ln|\frac{\frac12N_0}{N_0}|=-\lambda \times 130

\rightarrow ln|\frac{\frac12}{1}|=-\lambda \times 130

\rightarrow ln|1|-ln|2|-ln|1|=-\lambda \times 130

\rightarrow -ln|2|=-\lambda \times 130

\rightarrow \lambda= \frac{-ln|2|}{-130}

\rightarrow \lambda= \frac{ln|2|}{130}

We need to find the time when the sample remains 80% of its original.

N=\frac{80}{100}N_0

\therefore ln|{\frac{\frac {80}{100}N_0}{N_0}|=-\frac{ln2}{130}t

\Rightarrow ln|{{\frac {80}{100}|=-\frac{ln2}{130}t

\Rightarrow ln|{{ {80}|-ln|{100}|=-\frac{ln2}{130}t

\Rightarrow t=\frac{ln|80|-ln|100|}{-\frac{ln|2|}{130}}

\Rightarrow t=\frac{(ln|80|-ln|100|)\times 130}{-{ln|2|}}

\Rightarrow t\approx 42

We can use the sample about 42 days.

7 0
3 years ago
Tina completed 2/3 of her homework. George completed 7/8 of his homework. Who completed a greater fraction of homework
Amiraneli [1.4K]

get a common denominator of 24

2/3 * 8/8  vs 7/8 * 3/3

16/24 vs 21/24

16/24<21/24

2/3 <7/8

George did more work

6 0
3 years ago
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