The problem based on condition are solved using the unknown variables. The number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.
Given information-
The price of the tickets for the basketball game for adults is $4.00.
The price of the tickets for the basketball game for students is $2.50.
<h3>Variables</h3>Variables are the unknown and the value of the variables depend on the other variables in the equation. The above problem can be solved defining the variables from the given condition.
Let the total tickets purchased by the students is<em> x</em> and the total tickets porches by the adults is <em>y.</em>
As the total tickets sold for the game is $320. Thus,
.......1
Now as the total money with ticket selling is $1100. Thus,
Keep the value of u from the equation 1 in the above equation. We get,
Thus the number of tickets sold to the student are 120.
Keep this value in equation 1,
Thus the number of tickets sold to the adults are 200.
Hence the number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.
Answer:
Audrey can afford 4 hours of lesson.
Step-by-step explanation:
Given that:
Amount Audrey has to spend = $111
Cost of racket = $55
Cost per lesson = $14
Let,
y be the total cost
x be the number of hours
According to given statement;
y = 14x + 55
111 = 14x + 55
111 - 55 = 14x
14x = 56
Dividing both sides by 14
Hence,
Audrey can afford 4 hours of lesson.
Answer:
Step-by-step explanation:
Given that:
Population Mean = 7.1
sample size = 24
Sample mean = 7.3
Standard deviation = 1.0
Level of significance = 0.025
The null hypothesis:
The alternative hypothesis:
This test is right-tailed.
Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test
The test statistics can be computed as:
t = 0.980
Decision rule:
Since the calculated value of t is lesser than, i.e t = 0.980 < , then we do not reject the null hypothesis.
Conclusion:
We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.