∑ Hey, jillianwagler ⊃
Answer:
Step-by-step explanation:
<u><em>⇒ Given info:</em></u>
<em>Factor completely </em>
<u><em>⇒ Solution:</em></u>
<em>Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.</em>
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Applying difference of two squares formula:
Answer~:
<u><em>xcookiex12</em></u>
<em>8/19/2022</em>
Answer:
Step-by-step explanation:
Start with why C isn't the answer.
y = 1.8^0 . The power is zero. Anything to the zero power (anything except 0 to the 0 power) is 1. So 1.8^0 is 1 not something else. C assumes that somehow 0,1.8 turns into 1.8. It does not. The second part is also wrong but you don't need it. However here it is.
x = 0 y = 3
x = 1 y = 3 * 1.8 = 5.4
x = 2 y = 3 * 1.8^2 = 3*3.24 = 9.72
You should be able to see that if you multiply 5.4 by 3, you don't get 9.72
C just does not work.
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The actual answer is A. That's exactly what the graph does. If you multiply 5.4 * 1.8 you should get 9.72. Just for completeness, I've included the graph.
The operation between a rational and a irrational number that results in a rational number is a multiplication, hence the expression ab could represent a rational number.
<h3>What are rational and irrational numbers?</h3>
If a number can be represented by a fraction, it is rational, otherwise, it is irrational.
The addition/subtraction of a rational and an irrational numbers is irrational, while the multiplication is rational, hence the expression ab could represent a rational number.
More can be learned about rational numbers at brainly.com/question/10814303
Bottom right corner box is the answer.
Answer:
Step-by-step explanation:
In the two independent samples application, it involves the test of hypothesis that is the difference in population means, μ1 - μ2. The null hypothesis is always that there is no difference between groups with respect to means.
Null hypothesis: ∪₁ = ∪₂. where ∪₁ represent the mean of sample 1 and ∪₂ represent the mean of sample 2.
A researcher can hypothesize that the first mean is larger than the second (H1: μ1 > μ2 ), that the first mean is smaller than the second (H1: μ1 < μ2 ), or that the means are different (H1: μ1 ≠ μ2 ). These ae the alternative hypothesis.
Thus for the z test:
if n₁ > 30 and n₂ > 30
z = X₁ - X₂ / {Sp[√(1/n₁ + 1/n₂)]}
where Sp is √{ [(n₁-1)s₁² + (n₂-1)s₂²] / (n₁+n₂-2)}