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3 years ago

How would I do this at the bottom it says solution

Mathematics

1 answer:

Jlenok [28]3 years ago

4 0

Answer:

all you have to do is graph them but put them in y=mx+b form first, the coordinates is the solution

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Let t = cosA + sinA find values of t if 2 - sin2A = 2(cosA + sinA)

Zinaida [17]

$2 - \sin(2A) = 2(\cos A + \sin A)\\\\2-2\sin A\cos A=2\cos A+2\sin A\\\\2\sin A\cos A+2\cos A+2\sin A-2=0\\\\1+2\sin A\cos A+2\cos A+2\sin A-3=0\\\\\sin^2 A+\cos^2 A+2\sin A\cos A+2\cos A+2\sin A-3=0\\\\(\sin A+\cos A)^2+2\cos A+2\sin A-3=0\\\\(\sin A+\cos A)^2+2(\cos A+\sin A)-3=0\\\\\\t^2+2t-3=0\\\\t^2+2t+1-4=0\\\\(t+1)^2=4\\\\t+1=2\qquad\vee \qquad t+1=-2\\\\\\\boxed{t=1\qquad\vee\qquad t=-3}$

When $A\in\mathbb{R}$

$t=\cos A+\sin A\in[-\sqrt{2};\sqrt{2}]\approx[-1.4142;1.4142]$

and there is only one answer t = 1.

For $A\in\mathbb{C}$ both values are correct.

4 0

4 years ago

Can somebody help and explain this plzz

8_murik_8 [283]

A) Every T is worth 7 points, and every F is worth 3 points. So if we let T = 7 and F = 3, we can count how many T's and F's each team scored and write it as an expression.

So for the East Side Bulldogs, they have 7 touchdowns and 6 field goals, thus the expression for them is:

7T + 6F

For the West Side Bulldogs, they have 5 touchdowns and 5 field goals, thus the expression for them is:

5T + 5F

B) The difference would be written as:
7T + 6F - (5T + 5F) = 2T + F

C) To determine how many more points the winning team has than the losing team, calculate the scores of the two teams. Then subtract the smaller number from the larger number to determine the score differential.

8 0

4 years ago

CAN SOMEONE PLS ANSWER-If W(- 10, 4), X(- 3, - 1) , and Y(- 5, 11) classify AEXY by its sides . Show all work to justify your an

AnnZ [28]

Answer:

WX = $\sqrt{74} \approx 8.6023253\\\\$
XY = $2\sqrt{37} \approx 12.1655251\\\\$
WY = $\sqrt{74} \approx 8.6023253\\\\$
Classify: Isosceles

============================================================

Explanation:

Apply the distance formula to find the length of segment WX

W = (x1,y1) = (-10,4)

X = (x2,y2) = (-3, -1)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-3))^2 + (4-(-1))^2}\\\\d = \sqrt{(-10+3)^2 + (4+1)^2}\\\\d = \sqrt{(-7)^2 + (5)^2}\\\\d = \sqrt{49 + 25}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

Segment WX is exactly $\sqrt{74}$ units long which approximates to roughly 8.6023253

-------------------

Now let's find the length of segment XY

X = (x1,y1) = (-3, -1)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-5))^2 + (-1-11)^2}\\\\d = \sqrt{(-3+5)^2 + (-1-11)^2}\\\\d = \sqrt{(2)^2 + (-12)^2}\\\\d = \sqrt{4 + 144}\\\\d = \sqrt{148}\\\\d = \sqrt{4*37}\\\\d = \sqrt{4}*\sqrt{37}\\\\d = 2\sqrt{37}\\\\d \approx 12.1655251\\\\$

Segment XY is exactly $2\sqrt{37}$ units long which approximates to 12.1655251

-------------------

Lastly, let's find the length of segment WY

W = (x1,y1) = (-10,4)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-5))^2 + (4-11)^2}\\\\d = \sqrt{(-10+5)^2 + (4-11)^2}\\\\d = \sqrt{(-5)^2 + (-7)^2}\\\\d = \sqrt{25 + 49}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

We see that segment WY is the same length as WX.

Because we have exactly two sides of the same length, this means triangle WXY is isosceles.

8 0

3 years ago

Please help me!! do numbers 5-9 thanks PLEASE SHOW WORK ❤ (picture attached)

kenny6666 [7]

5) n - 5 > -2
 + 5 +5
 n > 3

6) 3 + x < 7
 -3 -3
 x < 7

7) -7y < 14
 ÷ -7 ÷ -7
 y < -2

8) b/5 > -1
 × 5 × 5
 b > -5

4 0

3 years ago

SOMEONE HELP ME PLZZZZ

konstantin123 [22]

Answer:

nice

Step-by-step explanation:

4 0

3 years ago